Magos.
Sure, but saying, "everything", is such a broad generalisation.
Operator associativity is well defined, but yes,
some operators do evaluate from right to left.
Here are some examples that have right associativity.
= The assignment operator.
++ Postfix increment operator.
++ Prefix increment operator.
There are quite a few more but I'll leave those to the inquisitive.
R.I.P C89
All their programs contain semi-colons and all of them print the wrong string.
I think you have to be more specific about the rules.
No, you just have to be less pedantic.
Who cares what the 8 translation phases of the c preprocessor do or what the compiler and linker add to the source code.
It was pretty straight forward, you're just another instance of the bollocks I have to contend with on this forum.
R.I.P C89
Then isn't my version valid?
why do you come here then?..., you're just another instance of the bollocks I have to contend with on this forum.
Last edited by major_blagger; 02-27-2004 at 09:17 AM.
To learn and share.Originally posted by major_blagger
why do you come here then?
R.I.P C89
Magos if you re-read I made sure to state that expressions were evaluated from left to right. Your example is not an expression.
Assignments are expressions-- they return the assigned value. If they didn't, you wouldn't be able to do things like a=b=c=3 in C.Magos if you re-read I made sure to state that expressions were evaluated from left to right. Your example is not an expression.
I thought the order of which the comma operator was evaluated was not defined in the standart, and thus, well, not standard?
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From the standard
6.5.17 Comma operator
Syntax
1 expression:
assignment-expression
expression , assignment-expression
Semantics
2 The left operand of a comma operator is evaluated as a void expression; there is a
sequence point after its evaluation. Then the right operand is evaluated; the result has its
type and value. If an attempt is made to modify the result of a comma operator or to
access it after the next sequence point, the behavior is undefined.
3 EXAMPLE As indicated by the syntax, the comma operator (as described in this subclause) cannot
appear in contexts where a comma is used to separate items in a list (such as arguments to functions or lists
of initializers). On the other hand, it can be used within a parenthesized expression or within the second
expression of a conditional operator in such contexts. In the function call
f(a, (t=3, t+2), c)
the function has three arguments, the second of which has the value 5.
The one who says it cannot be done should never interrupt the one who is doing it.
Note: The following is 100% personal opinion.
I personally don't call x = y = z = 5; expressions to avoid confusions with conditional expressions. To me expressions have to be simplified down and not assigned a value. Such as 3x -5 + 2x is simplified down to 5x - 5 (or 5(x-1) ) y == x + 5 is simplified down to true or false.
x = 5 I call assignment because that is what its doing. Now if you have x = y = z = 5 == 10; I would call the 5 == 10 an expression and the rest assignments.
But to avoid confusion from now on I'll refer to them as coniditional expressions.
