C program wierdness

ok i'm trying to learn c before moving on to c++ and this is what i get when compiling this in dev-c++

Code:

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#include<stdio.h>

int main()
{
    int a,b,c;
    a;
    b;
    c = a + b;
   
    printf("Enter the value of the first number: ");
    scanf("%d", &a);
    printf("Enter the value of the second number: ");
    scanf("%d", &b);

    printf("%d + %d = %d\n", a,  b, c);
   
    system("pause");
    return 0;
}

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the output (say i enter 5 and 7) is

5 + 7 = 8413188

anyone know what the deal is

well, you never actually get a real value in the variable c. You declare c as

Code:

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int c = a + b;

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at the beginning of the program, you want that after you accept the input, because when you do the above, you are putting the values of a and b AT THAT time, which are garbage values

EDIT:
also,

Code:

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a;
b;

---

does nothing, you are looking for

Code:

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a = 0;
b = 0;

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I would really recommend you read some of the tutorials on this site and others.

Code:

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c = a + b;

---

Local variables aren't initialized to anything in particular, so there is no way to predict what the value of c will be after this statement. Move it down in your code to a place after you give values to a and b but before you print.

Code:

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a;
b;

---

These don't do anything of use to you. All each statement does is evaluate the contents of a or b and do nothing with it. You can safely remove these two statements.

Code:

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system("pause");

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You must include stdlib.h to make the system function available.

Code:

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#include <stdio.h>
#include <stdlib.h>

int main()
{
    int a,b,c;

    printf("Enter the value of the first number: ");
    scanf("%d", &a);
    printf("Enter the value of the second number: ");
    scanf("%d", &b);
    c = a + b;
    printf("%d + %d = %d\n", a,  b, c);

    system("pause");
    return 0;
}

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