Thread: multiple inputs of multiple types

Im having trouble dealing with a program that takes multiple inputs (which can be a character, decimal, octal, hex) in any order. finding out if the input is a character or a digit.

When using argv it stores it as a string in a char array. I need to convert my input to a long or char depending on what it is. But I don't know the order, so i don't know what to expect. I trired using isalpha() but get Segmentation fault when executing.

If I knew what it was I could use strol(). Any ideas on how to deal with this??? Thank you.

Post the code you have along with any warnings and errors the compiler gives.

Code:

#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>

void convert();

int main(int argc, char* argv[]){
        convert(argc,argv);
        return 0;
}

void convert(int size, char* element[]){

	unsigned i;
	for(i=1;i<size;i++){
		if(isalpha(element[i])){
			char buffer;
   			strcpy(buffer,element[i]);
			printf("%c  %d  %x\n", buffer,buffer,buffer);
		}
		else{
			long buffer;
			if(isxdigit(element[i])){
				buffer = strtol(element[i],NULL,16);
				printf("%c  %d  %x\n", buffer,buffer,buffer);
			}
			else{
				strtol(element[i],NULL,10);
				printf("%c  %d  %x\n", buffer,buffer,buffer);
			}
		}
	}
}

during compile:

convert.c: In function `convert':
convert.c:18: warning: passing arg 1 of `strcpy' makes pointer from integer without a cast


Thanks.

When testing I figured that out and removed it from my post. Thanks for the reminder though Prelude.

Thanks for the help, I think im on the right track now.