Why does this give me an error at run time?...Code:struct vix { char *pname; int day; int month; int year; int hour; int min; } ; struct vix *pvix; pvix = malloc ( siz * sizeof *pvix ); for ( j = 0; j < siz; j++ ) fscanf(fp,"%d.%d.%d %d:%d %s",&(pvix+j)->day,&(pvix+j)->month,&(pvix+j)->year, &(pvix+j)->hour,&(pvix+j)->min,(pvix+j)->pname); for ( i = 0; i < siz; i++ ) printf("%d %d %s\n",i,(pvix+i)->day,(pvix+i)->pname); free(pvix);
>Why does this give me an error at run time?...
Where is (pvix+j)->pname pointing? (You need to allocate memory for it.)
7. It is easier to write an incorrect program than understand a correct one.
40. There are two ways to write error-free programs; only the third one works.*
>You need to allocate memory for it.
how would i do that?
btw the file contains something like
01.01.2003 00:00 test
11.11.2002 10:30 test2
etc...
> how would i do that?
Well the easy way is to make your structure member an array
char pname[20];
> &(pvix+j)->day
Too complicated
Try
&pvix[j].day
Just like what you would do if it were a regular array
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
ok, now there's no more errors but the output is strange :
0 0 ?
1 0 ?
2 0 ?
etc...
i use this to print :
Code:for ( i = 0; i < siz; i++ ) printf("%d %d %s\n",i,pvix[j].day,pvix[j].pname);
Code:for ( i = 0; i < siz; i++ ) printf("%d %d %s\n",i,pvix[j].day,pvix[j].pname);
7. It is easier to write an incorrect program than understand a correct one.
40. There are two ways to write error-free programs; only the third one works.*
hahai guess i'm blind , thanks Dave
