Keeping window open

I have written a very simple app with Visual C++, and when I compile the program, it runs fine. However, the window closes right away when I'd like for it to stay open until I hit a key....

what's the correct function to keep the window open?

I have attached the code of the program.

Code:

#include <stdio.h>
#include <stdlib.h>

struct process
{
		int memorySize;
		int processNumber;
		
		bool isExecuting;
		bool isOverflow;
		bool isStaged;
		bool isDone;


};

typedef struct process PROCESS;

void initNstart(PROCESS[], int, int);



main()
{	
	
	
	int totalExecSpace=64;
	int totalProcesses=5;
	
	PROCESS pr[5];

	initNstart(pr, totalProcesses, totalExecSpace);
	

	return 0;

}


void initNstart(PROCESS proc[], int size, int totalMem)
{
	void start(PROCESS[], int, int);

	int i;

	for (i=0; i<size; i++)
	{
		proc[i].processNumber=i+1;
		
		proc[i].isDone=false;
		proc[i].isStaged=false;
		proc[i].isExecuting=false;
		proc[i].isOverflow=false;

		printf("Enter Process Memory Size (not bigger than 64) For Process # %d\t", proc[i].processNumber);
		scanf("%d", &proc[i].memorySize);
		
		
		if(proc[i].memorySize>64)
		{
			printf("\n!You have entered size larger than size of Execute Q (64)! Size of process# %d is set to 30 MB\n", proc[i].processNumber);
			proc[i].memorySize=30;
		}

	}

	start(proc, size, totalMem);
}


void start(PROCESS proc[], int arraySize, int ExecMemSize)
{
	void PushExec(PROCESS[], int, int);
	void PushOver(PROCESS[], int);
	void PushStag(PROCESS[], int);
	void runTime(void);
	bool allDone(PROCESS[], int);

	do{
		PushStag(proc, arraySize);
		PushExec(proc, arraySize, ExecMemSize);
		PushOver(proc, arraySize);

		runTime();

	}while(!allDone(proc, arraySize));
}


bool allDone(PROCESS proc[], int size)
{
	int i;
	int d=size;

	for(i=0; i<size; i++)
	{
		if(proc[i].isDone==true)
		{
			d-=1;
		}
	}

	if(d==0)
		return true;
	else
		return false;

}


void PushStag(PROCESS proc[], int size)
{
	int q;
	
	for(q=0; q<size; q++)
	{
		if(proc[q].isDone!=true)
		{
			proc[q].isStaged=true;
			printf("\nProcess Number %d is in Staged Q with size %d\n", proc[q].processNumber, proc[q].memorySize);
		}
	}
}



void PushExec(PROCESS proc[], int size, int memLeft)
{
	int q;
	int sizeLeft=0;

	for(q=0; q<size; q++)
	{
		if(proc[q].isDone!=true)
		{
			
			if(memLeft>=proc[q].memorySize)
			{
				proc[q].isExecuting=true;
				proc[q].isDone=true;
				printf("\nTOTAL MEMORY LEFT = %d\nProcess Number %d is in EXEC Q with size %d\n", memLeft, proc[q].processNumber, proc[q].memorySize);
				memLeft-=proc[q].memorySize;
			}
		}
	}

}



void PushOver(PROCESS proc[], int size)
{
	int q;
	
	for(q=0; q<size; q++)
	{
		if(proc[q].isDone!=true)
		{
			if(proc[q].isExecuting==false && proc[q].isStaged==true)
			{
				proc[q].isOverflow=true;
				printf("Process Number %d is in OVERFLOW Q with size %d", proc[q].processNumber, proc[q].memorySize);
			}
		}
	}
}


void runTime(void)
{
	float k;
	for(k=0; k<10000000; k++);
}

Just before the return o; add getchar();

This will wait for the user to hit return before the program exits and the window closes. You may add a prompt before the getchar if you wish.

The program runs fine if I compile it with Visual C++ with the new code - but it still closes immediately if I run the executable.

>but it still closes immediately if I run the executable
Then you still have a newline sitting in stdin. To get rid of it, use

Code:

fflush ( stdin );

...just kidding, don't do that. A better way is to avoid scanf altogether using fgets and sscanf, but you can also take the easy way out by replacing that call to getchar with:

Code:

/* Clear out stdin */
while ( getchar() != '\n' )
  ;
/* Now wait for user input */
getchar();

or put a while(1); at the end, and hit control-c when done.

thanks! that worked...