Array from 1 to n

**Hexxx** · 11-21-2003

I'm suppose to make and print an array (it's for a game) for selecting numbers from 1 to n. Like if the number entered is 6, then the numbers in the games are "1 2 3 4 5 6" They are only positive nos, so I can put 0 in the 1st array index so things can be easier to follow, so that 1 is in the 1st, 2 in the 2nd, and n in the nth. But when I use this code, I get that there is a ) missing in the printboard function.

Code:

#include <stdio.h>
#include <conio.h>
int main(void) {
void makeboard(int board[], int size);
int board[101];
int size;
printf ("Enter size:-");
scanf ("%d", &size);
makeboard(board,size+1);
printboard(board,size+1);
return 0;
}


void makeboard(int board[], int size) {
int i;
for (i=0; i<=size; i++) board[0]=i;
}

void printboard (char board[], int size+1) {
for (int i=0; i<=size+1; i++) {
if (board[i]!=0) printf ("%d ", board[i]);}

**Salem** · 11-21-2003

> for (int i=0
This isn't valid C, its C++

**Prelude** · 11-21-2003

You have quite a few syntax errors and type mismatches. Compare this to what you had before:

Code:

#include <stdio.h>

void makeboard(int board[], int size);
void printboard(int board[], int size);

int main(void) {
  int board[101];
  int size;
  printf ("Enter size:-");
  scanf ("%d", &size);
  makeboard(board,size+1);
  printboard(board,size+1);
  return 0;
}

void makeboard(int board[], int size) {
  int i;
  for (i=0; i<size; i++) board[i]=i;
}

void printboard (int board[], int size) {
  int i;
  for (i=0; i<size; i++)
    if (board[i]!=0) printf ("%d ", board[i]);
}

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