Looking at strings

(in C and only in C)
hi, im reading from a file a number of items, eg....
add(15);
sum();
add(100);
sum();
ok.......
I am tokenizing the file then putting the tokens in an array. I then want to look at each token and then get the value from with the brackets of the add tokens

eg add(50) value = 50.

Cant think of a way to do this, can someone please help??? with a bit of code i could use?

Thankyou very much in advance

Well, I won't do your homework for you but I'll give you an idea where you could start.

I would start by making functions for the strings you read in... like a function for add(), sum(), etc

And then in the main method, I would actually do the reading from the file and call the methods it asks for.

Alexisa

***THIS ISNT A HOMEWORK QUESTION*******

Ok let me get rid of some of the extra detail and ask a simplier question,

i have a string, there is(definatley) a number within the string, how can i find out the number???

eg


ifthenumberinthebracketsis50iwillbeveryhappy(50);

This dos not mean that ifthenumberinthebracketsis50iwillbeveryhappy is a function but just a string.

You could start with the strchr() function to locate the positions of the parentheses

Or perhaps a simple loop using isdigit to test each character for validity.

Quzah.

Quote:

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Originally posted by quzah
Or perhaps a simple loop using isdigit to test each character for validity.

Quzah.

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Another option: you can use strcspn() to achieve a similar result.

Quote:

---

Originally posted by quzah
Or perhaps a simple loop using isdigit to test each character for validity.

Quzah.

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That won't work based on his example. Find the open paren and test/read the number.

Quote:

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Originally posted by WaltP
That won't work based on his example. Find the open paren and test/read the number.

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Sure it would.

Code:

---

for( x = 0; s[x]; x++ )
{
    if( x > 0 && isdigit( s[x] ) && s[x-1] == '(' )
        printf("See? It works. You just have to be creative.\n");
}

---

Quzah.

Quote:

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Originally posted by quzah
Sure it would.

Code:

---

for( x = 0; s[x]; x++ )
{
    if( x > 0 && isdigit( s[x] ) && s[x-1] == '(' )
        printf("See? It works. You just have to be creative.\n");
}

---

Quzah.

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OK, smartypants, try it on
ThisIsA30CharacterFunctionName(15) without the paren check, as you implied before! :rolleyes: :)

Quote:

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Originally posted by WaltP
OK, smartypants, try it on
ThisIsA30CharacterFunctionName(15) without the paren check, as you implied before! :rolleyes: :)

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I didn't say anything about a paren check. I said a simple loop using isdigit. My last example fits that description. :D


Quzah.