I am not mainly asking about a code but I would like to have
some help with how to start logically with solving this series:
II=4*(1-1/3+1/5-1/7+1/9-1/11+1/13-.....)
the program will ask the user about the number of terms he
wants,
and then depend on these terms calculate and display the
approxmation of II.
for ( i = 1 ; i <= 13 ; i += 2 )
That generates all the denominators for your terms in your series
int sign = 1;
sign = sign * -1;
If you keep doing that in a loop, sign alternates between +1 and -1
Use this to alternately add and subtract successive terms
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
many thanks for your great help.
