While loop question

This is just a portion of my code and I know everything else works properly, but I need the code to check and see if the user entered a valid input (either 'H', 'S', or 'C'). I want the program to loop until the user inputs a valid variable, but when the user initially puts in one of the variables the program just hangs. It works fine if the user enters an invalid answer (it loops until a valid answer is entered) but then hangs again. Any ideas? I'm thinking the while loop is the issue...how do I get it to work? Thanks.

Code:

while ( ( status = getchar() ) != 'H' || 'S' || 'C' )
{
   switch ( status )
   {
      case 'H':   
      case 'h':  
        break;

      case 'S':  
      case 's':  
        break;

     case 'C':   
     case 'c':    
        break;

     case '\n':  
     case '\t':   
     case ' ':   
        break;

     default: /* Catches all characters that are not valid entries */
        printf("Incorrect status value entered.\n");
        printf("Enter a valid status value [H for hourly, S for salaried staff, or C for contractor]:\n");
   }
}

What's wrong with this code?

Code:

int n = 5;

//do something if n is 5 or 3 or 1
if (n == 5 || 3 || 1)
{
...
}

gg

[EDIT]
Solution:

Code:

//do something if n is 5 or 3 or 1
if ((n == 5) || (n == 3) || (n == 1))
{
...
}

I tried doing that as well, but it still doesn't work, unless I am missing something obvious...Thanks.

Code:

while ( ( status = getchar() != 'H') || ( status = getchar() != 'S') || ( status = getchar() != 'C') )
{
...
}

Here's one way

Code:

#include <stdio.h>

int main(void)
{
  int c;
  int Invalid = 1;

  while (Invalid && (c = getchar()) != EOF)  
  {
    Invalid = 0;
    switch (c)
    {
    case 'H': puts("H entered"); break;
    case 'I': puts("I entered"); break;
    case 'J': puts("J entered"); break;
    default:  
      puts("Invalid! "); 
      Invalid = 1; 
      while ((c = getchar()) != '\n' && c != EOF); /* Flush input buffer */
      break;
    }
  }

  return(0);
}