Looking to find out how to write a program in C to calcilate Eulars number. The following formula is used for the e=1+1/1!+1/2!+1/3!+1/4!+1/5!+1/6!...+1/(n-1)!+1/n!.
The program needs to approximate e using a loop that terminates when the difference between 2 consecutive numbers differs by less than .0000001.
I have been working on this for a while and just need some pointers.
Thanks,
Sparky
So post some code then, and lets see where you've got to
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
Hate to break it to ya, but you're screwed. Floating point numbers tend to not be that great for precision.The program needs to approximate e using a loop that terminates when the difference between 2 consecutive numbers differs by less than .0000001
Quzah.
Hope is the first step on the road to disappointment.
