displaying float digits

[Dimeslime]

Hey there, i'm curious on how to display the first and rightmost digit of the integral portion of a floating point integer. I'm not quite sure how to do this.

whould I create a two variables like so:

float floatintPointInt;
float result;

....

result = floatingPointInt % floatingPointInt / 10;

....

Thanks

[Wledge]

int result = (int)floatingPointInt % 10;

[Dimeslime]

Thanks a lot man.

[Dimeslime]

Hi, i'm sorry.. I'm not quite sure what is wrong with my code.
It's supposed to print the first and the second rightmost digit of the integral portion of the float.

int main()
{
	float decimal = 0.0;
	int result = (int)decimal % 10;

	printf("Floating point Int: ");
	scanf("%f", result);
   

	printf("\n\n%f", result);

	return 0;
}

I'm not sure if i should assign the "decimal" to 0.0.. when i don't the compiler give an error.

thank you.

[Dave_Sinkula]

>I'm not sure if i should assign the "decimal" to 0.0.. when i don't the compiler give an error.
An error? Or a warning that you are using the value of 'decimal' before it has been initialized?

>scanf("%f", result);
Here scanf expects a pointer to a float -- give it one.

scanf("%f", &decimal);

Convert the float 'decimal' to the int 'result' after you've gotten 'decimal'.

>It's supposed to print the first and the second rightmost digit of the integral portion of the float.
You may want to use % 100.

>printf("\n\n%f", result);
Use %d with an int.

printf("\n%d\n", result);

[Dimeslime]

Oh geeeezzz.. man.. thank you so much.

I can't believe i missed that scanf("%d", &result);........... bahhh

Thank you