Hi,
I am new to c. I was trying to print out this message using pointers.
This is a test
No - it is not a test
This is my code.
Your help will be appreciated.Code:#include<stdio.h> #include<string.h> #include<stdlib.h> int main(){ char *p = "This is a test"; printf("%s\n",p); strcat(p,"No - this is a test"); printf("%s\n",p); }
not sure, but I think when you use char *p = "hi"; that you make a constant, you can't alter it because the compiler allocated space only for those character, I think...
Correct. They're using string literals, and as such, you cannot (read: shouldn't try to) modify them.Originally posted by chrismiceli
not sure, but I think when you use char *p = "hi"; that you make a constant, you can't alter it because the compiler allocated space only for those character, I think...
You'll probably want an array for the first sentence, long enough to hold them both. Either that or do it dynamicly. But an array should suffice for this.
However, if your code actually did work, you would end up with this output:
strcat adds one string to the end of another. It doesn't replace the first string with the second.This is a test
This is a testNo - this is a test
If you really want the first string overwritten, you'd need to use strcpy (or strncpy) or something similar.
Quzah.
Hope is the first step on the road to disappointment.
