Thread: increment IP addresses - newbie Q.

  1. #1
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    increment IP addresses - newbie Q.

    sorry if this has been answered before- 'search' didn't return anything though...

    I use a gethostbyname() to get an IP address: 10.10.10.3

    I need a procedure to fill an array with a range of IP's (10.10.10.(i++)):

    10.10.10.4
    10.10.10.5
    10.10.10.6
    ...

    and so on...

    is there a simple way to do it, or should I convert an IP to char*, cut off the last IP part, convert it to int, increment it (check if > 255) , convert back to char*, concatenate strings....

    sounds awfully complex for such a simple task...

    thanks in advance,

    W.

  2. #2
    Code Goddess Prelude's Avatar
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    >sounds awfully complex for such a simple task...
    IP addressing doesn't exactly make it easy though. Of course, you could just convert the entire address to an array of integers and work with that:
    Code:
    int i = 0;
    int j;
    int ip[4];
    char hostaddr[16];
    char *snip;
      
    /* Put an ip string in hostaddr */
    for (snip = strtok(hostaddr, "."); snip != NULL; snip = strtok(NULL, "."))
      ip[i++] = atoi(snip);
    
    for (j = 0; j < 4; j++)
      printf("%d%s", ip[j], (j == 3) ? "\n" : ".");
    My best code is written with the delete key.

  3. #3
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    thanks, Sandra.

    would it be a good idea to use:

    Code:
    unsigned b1, b2, b3, b4;
    unsigned char c;
    int abc = sscanf(ipadd, "%3u.%3u.%3u.%3u%c", &b1, &b2, &b3, &b4, &c);
    and then work with b4?

  4. #4
    Code Goddess Prelude's Avatar
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    You could do that too, there are a number of approaches to this problem.
    My best code is written with the delete key.

  5. #5
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    Why not do it the easy way for your computer, convert the IP to binary, and simply do binary math incrimenting by one each time. Then its a simple matter to convert 4 binary octets back to ints. This is way easier than screwing around with a confusing thingy where you manually have to keep track of a base 256 number.

  6. #6
    Guest Sebastiani's Avatar
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    There's an even easier way.

    Ip's are stored as unsigned long integers. That's 4 bytes of data.
    To manipulate these bytes 'easily', the creators of the socket specification came up with this ridiculous structure:


    Code:
     struct in_addr 
    {
      union 
     {
         struct 
       { 
         u_char s_b1,
                     s_b2,
                     s_b3,
                     s_b4; 
       } S_un_b;
    
         struct 
       { 
         u_short s_w1,
                      s_w2; 
       } S_un_w;
    
        u_long S_addr;
    
     } S_un;
    };

    Basically just a container for an unsigned long of course.

    So to access byte[0] we 'simply' navigate to in_addr::S_un.S_un_b.s_b1 (!)

    That's a bit complicated for such a trivial task!

    So here's a simpler approach:

    Code:
    unsigned char 
     get_subnet(unsigned long address, int which)
    {
     return ((unsigned char*)&address)[which];
    }
    
    
    unsigned long 
     set_subnet(unsigned long * address, int which, unsigned char what)
    {
     ((unsigned char*)address)[which] = what;
     return *address;
    }

    Of course, the above could be coded as a macro, if necessary.

    So here's an example of putting this simple little scheme to work:

    Code:
    #define MAX 256
    
    int main()
    {
     char buff[MAX];
     
     unsigned long address;
     
     int byte;
         
     printf("Enter a valid ip address > ");
     
     fgets(buff, MAX, stdin);
     
        if((address = inet_addr(buff)) != INADDR_NONE)
       {
        printf("Which subnet to manipulate? [0-3] > ");
        
           if((byte = atoi(fgets(buff, MAX, stdin))) < 4)
          {
              for(int i = get_subnet(address, byte)+1; i < MAX; ++i)
             {
              set_subnet(&address, byte, i);
              
              printf("%s\n", inet_ntoa((in_addr&)address));
             }         
          }      
       }
     system("PAUSE");
    }

    >> int abc = sscanf(ipadd, "%3u.%3u.%3u.%3u%c", &b1, &b2, &b3, &b4, &c);


    That's not really necessary. The inet_addr() function takes a dotted decimal string and converts it to an unsigned long.

    Then you have the inet_ntoa() function that does just opposite (though you have to cast the unsigned long to an in_addr).

    So between the two, you can convert back and forth rather easily, ie:

    printf("%s", inet_ntoa(inet_addr(inet_ntoa(inet_addr("127.0.0.1 ")))));

    - prints "127.0.0.1", of course.



    Anyway, I hope that helps.

    Happy coding.
    Code:
    #include <cmath>
    #include <complex>
    bool euler_flip(bool value)
    {
        return std::pow
        (
            std::complex<float>(std::exp(1.0)), 
            std::complex<float>(0, 1) 
            * std::complex<float>(std::atan(1.0)
            *(1 << (value + 2)))
        ).real() < 0;
    }

  7. #7
    Registered User
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    10
    thanks, ppl.
    you have really helped.

    see ya

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