Concatenating characters

This is a discussion on Concatenating characters within the C Programming forums, part of the General Programming Boards category; How can I concatenate characters in C? and if those 2 characters are numbers for example, say char1 = 1, ...

  1. #1
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    Concatenating characters

    How can I concatenate characters in C?

    and if those 2 characters are numbers for example, say char1 = 1, char2 = 4

    so if i merge them, it will become 14

    can i then manipulate htis value to perform mathematical calculations?
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  2. #2
    Code Goddess Prelude's Avatar
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    Make a string out of the characters, use strtol to turn the result into a number, repeat as necessary for other values, then do your calculations.
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  3. #3
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    Re: Concatenating characters

    Originally posted by fkheng
    How can I concatenate characters in C?

    and if those 2 characters are numbers for example, say char1 = 1, char2 = 4

    so if i merge them, it will become 14

    can i then manipulate htis value to perform mathematical calculations?
    You need to define a character buffer, like
    char buf[10]; /* to hold a string of 9 characters */

    Then add char1 and char2 into the buffer:
    Code:
    buf[0] = char1;
    buf[1] = char2;
    buf[3] = '\0';    /* End the 'string' with a null */
    If you know they are numbers, use atoi() to convert them from a string into int
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    okay, er........say i have used atof to convert a string to float

    it is a float number

    and it looks like e.g. 60.00000

    from this, what if i just want 2 floating points, i mean just 60.00

    how do i shorten it to this?
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  5. #5
    Just Lurking Dave_Sinkula's Avatar
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    >and it looks like e.g. 60.00000

    I might assume that looks means you have chosen the default precision by which printf displays the number's representation.

    >from this, what if i just want 2 floating points, i mean just 60.00
    >how do i shorten it to this?

    If the above assumption is true, then you do nothing to the number; you change the precision by which you tell printf to display its representation. For example,
    Code:
    #include <stdio.h>
    
    int main(void)
    {
       double number = 60.0;
       printf("number = %f\n",   number); /* default precision */
       printf("number = %.2f\n", number); /* 2 digits after decimal point */
       return 0;
    }
    
    /* my output
    number = 60.000000
    number = 60.00
    */
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