Thread: No output from this program

  1. #1
    Registered User
    Join Date
    Jun 2003
    Posts
    10

    No output from this program

    Here's the problem:
    a. Write a C program that has a declaration in main() to store the string "Vacation is near" into an array named message. There should be a function call to display() that accepts mesage in a parameter named strng and then displays the message using the pointer notation *(strng + i).
    b. Modify this display() function to alter the address in message. Use the expression *strng rather than *(strng + i) to retrieve the correct statement.

    Here's the code I have so far:

    Code:
    #include <stdio.h>
    void display(char[]);
    int main()
    {
      char message[] = "Vacation is near";
      display (message);
    return 0;
    }
    
    void display(char strng[])
    {
    int i=0;
    while(*(strng + i) != '\0'
    {
    printf("%c", *(strng+i));
    i++;
    }
    printf("\n");
    return;
    }

  2. #2
    Been here, done that.
    Join Date
    May 2003
    Posts
    1,164

    Re: No output from this program

    Good job using code tags! Now use indentation to make the code more readable.

    Do you have a question? So far it looks fine to me.
    Definition: Politics -- Latin, from
    poly meaning many and
    tics meaning blood sucking parasites
    -- Tom Smothers

  3. #3
    Registered User
    Join Date
    Jun 2003
    Posts
    10
    The problem is whenever I run the program I just get a blank window. It doesn't print out the vacation is near statement and I'm not sure why??

  4. #4
    Been here, done that.
    Join Date
    May 2003
    Posts
    1,164
    Me neither. Works for me once it compiled properly.
    Definition: Politics -- Latin, from
    poly meaning many and
    tics meaning blood sucking parasites
    -- Tom Smothers

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