wanna return to main function after command input, but this exits to windows...help!

This is a discussion on wanna return to main function after command input, but this exits to windows...help! within the C Programming forums, part of the General Programming Boards category; hi ppl i have a simple question, i'm starting to learn C and i spotted this problem . my program ...

  1. #1
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    wanna return to main function after command input, but this exits to windows...help!

    hi ppl i have a simple question, i'm starting to learn C and i spotted this problem . my program after any command that i input just exits, and it's very annoying to just restart the whole program. i'll put here the source code(it's far from finished but the start and end are there) so that you can easily tell me what to put and where to put exactly:
    #include <stdio.h>
    #include <stdlib.h>


    int main(int argc, char *argv[])
    {

    int x;
    int CErnesto;
    int CZeManel;

    int Andre;
    int Angelo;
    int Diogo;
    int Ernani;
    int Jorge;
    int Rui;
    int Sergio;
    int Tiago;

    int Bruno;
    int Filipa;
    int Filipe;
    int Lara;
    int Mafalda;
    int SofiaE;
    int SofiaP;
    int Susana;

    int EquipaGolfinho;
    int EquipaLeao;

    int Ajuda;


    CErnesto=1;
    CZeManel=2;
    Andre=3;
    Angelo=4;
    Diogo=5;
    Ernani=6;
    Jorge=7;
    Rui=8;
    Sergio=9;
    Tiago=10;
    Bruno=11;
    Filipa=12;
    Filipe=13;
    Lara=14;
    Mafalda=15;
    SofiaE=16;
    SofiaP=17;
    Susana=18;
    EquipaGolfinho=19;
    EquipaLeao=20;
    Ajuda=118;

    printf(" Introduza o numero correspondente a informacao que pretende ou\npressione 118 para ajuda com os numeros correspndentes: ");
    scanf( "%d", &x );
    if (x==Ajuda)
    {
    printf("\nCErnesto=1\nCZeManel=2\nAndre=3\nAngelo= 4\nDiogo=5\nErnani=6\nJorge=7\nRui=8\nSergio=9\nTi ago=10\nBruno=11\nFilipa=12\nFilipe=13\nLara=14\nM afalda=15\nSofiaE=16\nSofiaP=17\nSusana=18\nEquipa Golfinho=19\nEquipaLeao=20\n\n");
    }
    if (x==Diogo)
    {
    printf("Nome completo: Diogo Alexandre Nasceu a: 22/12/1987 \nTotem: Preguica Preguicosa\n");
    system("PAUSE");
    }
    else
    system("PAUSE");
    }

    it's just that, for the moment. please i'd appreciate some help as as far that i know it's very simple, but i just can't reach it....i've tried some switch and loops but i don't know exacly what to put nor where...

    Thanks

  2. #2
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    So you want to continue to let the user input various things. What you want is a while loop. Here is how it works and you can incorporate it into your program.

    Code:
    int num = 0;
    
    while( num != -1 ) // Here is the condition that has to be met
    {
      printf( "Enter a number (-1 quits): " );
      scanf( "%i", &num );
    
      printf( "You put %i", num );
    }
    So you want to continue taking input until a condition is met. This loop will go on as expected while the condition evaluates to TRUE.
    "...the results are undefined, and we all know what "undefined" means: it means it works during development, it works during testing, and it blows up in your most important customers' faces." --Scott Meyers

  3. #3
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    so i should put it in the beginning, like this? :
    Code:
    #include <stdio.h>
    #include <stdlib.h>
    
    
    int main(int argc, char *argv[])
      {
    
    int x;
    int CErnesto;
    int CZeManel;
    
    int Andre;
    int Angelo;
    int Diogo;
    int Ernani;
    int Jorge;
    int Rui;
    int Sergio;
    int Tiago;
    
    int Bruno;
    int Filipa;
    int Filipe;
    int Lara;
    int Mafalda;
    int SofiaE;
    int SofiaP;
    int Susana;
    
    int EquipaGolfinho;
    int EquipaLeao;
    
    int Ajuda;
    
    
    CErnesto=1;
    CZeManel=2;
    Andre=3;
    Angelo=4;
    Diogo=5;
    Ernani=6;
    Jorge=7;
    Rui=8;
    Sergio=9;
    Tiago=10;
    Bruno=11;
    Filipa=12;
    Filipe=13;
    Lara=14;
    Mafalda=15;
    SofiaE=16;
    SofiaP=17;
    Susana=18;
    EquipaGolfinho=19;
    EquipaLeao=20;
    Ajuda=118;
    
    int num =0;
    while( num != -1 ) // Here is the condition that has to be met
    {
    
    
       printf("  Introduza o numero correspondente a informacao que pretende ou\npressione 118 para ajuda com os numeros correspndentes: "); 
       scanf( "%d", &x );
    if (x==Ajuda)
      {
       printf("\nCErnesto=1\nCZeManel=2\nAndre=3\nAngelo=4\nDiogo=5\nErnani=6\nJorge=7\nRui=8\nSergio=9\nTiago=10\nBruno=11\nFilipa=12\nFilipe=13\nLara=14\nMafalda=15\nSofiaE=16\nSofiaP=17\nSusana=18\nEquipaGolfinho=19\nEquipaLeao=20\n\n");
      }
    if (x==Diogo)
      {
       printf("Nome completo: Diogo Alexandre Nasceu a: 22/12/1987 \nTotem: Preguica Preguicosa\n");
       system("PAUSE");
      }
    else
       system("PAUSE");
      }
      }
    like this? or did i put it wrong? if wrong can you point exacly where do i have to put it in?

    thanks for help as for now
    Last edited by Slaught; 07-14-2003 at 05:46 PM.

  4. #4
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    Well a few things. First of all, you need to put a return 0 statement in as the last line in your main function. You specify that it will return an int but you never return anything. Even though it may compile it is incorrect. Also you are checking while( num != -1 ) but when you take input from the user you set it to the variable x. So take out the int num = 0; and change the while loop to while( x != -1 ) and it should be fine. You might want to also inform the user that -1 quits the program.
    "...the results are undefined, and we all know what "undefined" means: it means it works during development, it works during testing, and it blows up in your most important customers' faces." --Scott Meyers

  5. #5
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    forget the last thread, i did some logical experimenting and found the way to do it.
    thanks a lot MrWizard . You were really a great help. BTW, do you know the command to clear screen?

  6. #6
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    This is an implementation dependent discussion.

    Read this and it should help:

    http://faq.cprogramming.com/cgi-bin/...&id=1043284385
    "...the results are undefined, and we all know what "undefined" means: it means it works during development, it works during testing, and it blows up in your most important customers' faces." --Scott Meyers

  7. #7
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    Got it already. Thanks man i really appreciated your help, despite my questions being a bit noobish you helped me .

    Really thanks, now i can finish this goddamn program hehe.

  8. #8
    Just because ygfperson's Avatar
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    some advice...

    use enum to declare your names. ie:

    enum colors {black=1, brown, blue, red};

    black would be 1, brown 2, blue 3, and red 4

    It's a bit more complicated, but not much.

  9. #9
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    What's the point in doing that to declare them? i didnt get it...
    BTW, is it possible to, like, put a "kind of password" in the beginning of the program to multi users, giving each user a different pass, using the if and else command in the beginning, like:

    Code:
    int user1, pass1;
    user1=x
    pass1=y
    printf("Input user and pass ");
    scanf( "%d%d", &user1, &pass1);
    if (user1==x)
    continue;
    else
    break;
    if (pass1==y)
    continue;
    else
    break;
    i think this method works, but it is to only one user and pass. What have i to do to ask for more than 1 user and pass, being all users different and so the passes?
    Last edited by Slaught; 07-14-2003 at 05:45 PM.

  10. #10
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    Originally posted by Slaught
    What's the point in doing that to declare them? i didnt get it...
    BTW, is it possible to, like, put a "kind of password" in the beginning of the program to multi users, giving each user a different pass, using the if and else command in the beginning, like:

    int user1, pass1;
    user1=x
    pass1=y
    printf("Input user and pass ");
    scanf( "%d%d", &user1, &pass1);
    if (user1==x)
    continue;
    else
    break;
    if (pass1==y)
    continue;
    else
    break;


    i think this method works, but it is to only one user and pass. What have i to do to ask for more than 1 user and pass, being all users different and so the passes?
    use a struct to hold the pw variable, user name, etc. Use the define statement to declare your set value for the password.

    typedef struct data1
    {
    int password;
    char name[20];
    } user;

    user mydata[MAXUSERS];

    loop through asking each of MAXUSERS his or her name and password, but I'd suspect that you'd be better off using a char array for the password than you would an int....
    I haven't used a compiler in ages, so please be gentle as I try to reacclimate myself. :P

  11. #11
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    Question

    huh, like, i never worked with that kind of function, so i dont really know how to input users and passes in there for "making the loop"....can u put an example of that, with at least 3 different users and 1 unique pass for each one?

    Thanks!
    Last edited by Slaught; 07-14-2003 at 05:50 PM.

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