Er.....i want to detect if a character is a number between 0 and 9
i achieve this using ascii rite? er......how do i specify this in the if statement?
Er.....i want to detect if a character is a number between 0 and 9
i achieve this using ascii rite? er......how do i specify this in the if statement?
Only by the cross are you saved...
Code:#include <stdio.h> int main() { char test1 = 'a'; char test2 = '2'; function(&test1); function(&test2); return 0; } int function(char *test) { if(*test < '0' || *test > '9') { printf("not a character between 0-9\n"); return 1; } printf("is a character between 0-9\n"); return 0; }
The standard library function isdigit will return true if the character is a digit.Code:#include <stdio.h> #include <ctype.h> int main(void) { char *ptr, number[] = "*_42-Aa0"; for ( ptr = number; *ptr != '\0'; ++ptr ) { if ( isdigit(*ptr) ) { printf("'%c' is a digit\n", *ptr); } else { printf("'%c' is not a digit\n", *ptr); } } return 0; } /* my output '*' is not a digit '_' is not a digit '4' is a digit '2' is a digit '-' is not a digit 'A' is not a digit 'a' is not a digit '0' is a digit */
Last edited by Dave_Sinkula; 06-22-2003 at 10:52 PM.
7. It is easier to write an incorrect program than understand a correct one.
40. There are two ways to write error-free programs; only the third one works.*
Well, since you are talking about characters, and not numbers- you could just say:Originally posted by fkheng
Er.....i want to detect if a character is a number between 0 and 9
i achieve this using ascii rite? er......how do i specify this in the if statement?
dCode:void foo(void) { char myLetter; myLetter = 'j'; /* stuff a non-digit value in */ if((myLetter <= '9') && (myLetter >= '0')) Success(); else Failure(); }
i see, thanx, many alternatives to the code...
about the isdigit, i recall using it, but somehow it could not detect number characters, i really do not know y...anyway, thanx ppl, the codes work!
Only by the cross are you saved...
