Thread: question ?

Sorry, the moderator in me couldn't take it anymore, I just had to merge the two threads.

Alright, I'll post mine. Like the 'recursive main' call, mine is recursive also. However, mine is ANSI compatible, and does in fact print 1 to N in order:

Code:

#include <stdio.h>
void ntimes( void )
{
    static int n = 1;
    printf("n is %d\n", n );
    fflush( stdout );
    ntimes( );
}

int main( void )
{
    printf(
    "This program prints the numbers 1 to N,\n"
    "where N is the available stack space\n",
    "divided by the overhead of the call\n",
    "to the function itself. Hey, you never\n",
    "set a requirement for N, that's your\n",
    "own fault.\n"
    );

    ntimes( );
    return 0;
}

There ya go.

*whistles innocently*

Quzah.

Code:

#include<stdio.h>
int main()
{int n,func1();
printf("enter the value of n");
scanf("%d",&n);
func1(n);
}
int  func1(int n)
{static int k=1;
int t=0;
int m;
     t=k^n;
     printf("\n%d",k);
     ++k;
     m=t||exit(0);/*this is a short circuit operation using or*/
     func1(n);
}

the main reason why m=t||exit(0) is used is that till the end number and the current number is not same t is always 1
due to XOR operation so when t is 1 in m=t||exit(0)
compiler does not check the or statement.
so when t is 1 compiler skips exit(0)
and next func1 is called.
once the number n and k become equal t is 0 due to XOR
thus when m=t||exit(0)
is evaluated the second part of the exp is checked and the loop terminates.

You didn't prototype func1 (or give it a return type), main returns an int, and what in the heck is this: 'm=t||exit(0);'?

Also, use code tags.

Originally posted by XSquared
Also, use code tags.

Also, stop making new threads. Hammer, want to merge this (again!)?

Your code (after I correct it so it would compile without error) does nothing other than exiting after the first function call. Perhaps you should actually try running your code?

Quzah.

Originally posted by AProg
You are losing your time is a silly problem.
All solutions that have been posted are for the recycle bin.
This is not a problem - problems have a purpose and a solution. This has neither purpose nor solution.

It certainly does have a purpose. Gets us to think outside the box, exercises the gray cells, and makes us either get behind at work or loose sleep, both are requirements for professional programmers.

Also, just because you don't agree with a solutions doesn't mean it's not a solution. Maybe we just haven't hit the proper solution yet

Originally posted by AProg
You are losing your time is a silly problem.
All solutions that have been posted are for the recycle bin.
This is not a problem - problems have a purpose and a solution. This has neither purpose nor solution.

Yes, it does have a purpose. Makes you think and use the language in a way most people don't use it. You are more than welcome to not participate if you don't want to.

Originally posted by AProg
>Gets us to think outside the box, exercises the gray cells, and makes us either get behind at work or loose sleep, both are requirements for professional programmers.
Nop, you are wrong.

[rant]Bull. I stated an opinion and my opinion is not wrong. You may disagree, that's your decision to make, but to tell me I'm wrong to hold that opinion is very arrogant. As a programmer since the 70's, I have a better grasp of what's useful than someone that's still learning.[/rant]
(I obviously dislike being told I'm wrong by someone that's clueless to the realities)

Before some days, someone gave me a chess problem. I troubled my mind too long, i lost my sleeps and i spent most time thinking about that problem. I couldn't find the answer. I was too closed....

Hmmm, so it was OK once to have a problem you can't solve, but you should never have a second one? Better find a new career (or hobby). Go flip burgers or something. Fewer unsolvable problems exist.

Originally posted by AProg
Well, i could only take this "problem" ( oh God what i am saying! ) as a joke.

>You are more than welcome to not participate if you don't want to.
Participate to what??? Your joke or your party?!?!

To participate in the conversation, if you don't like it then quit reading this post.

I think this can be done recursively..........

Isn't it.............. ???