Sqrt() Function

This is a discussion on Sqrt() Function within the C Programming forums, part of the General Programming Boards category; hi everyone...just wanna say thanks for everyone that help me so far since i'm very new to C. the problem ...

  1. #1
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    Sqrt() Function

    hi everyone...just wanna say thanks for everyone that help me so far since i'm very new to C.

    the problem asked to write a C function name root4() that returns the fourth root of the argument passed to it. in writing root4() use the sqrt() library function.

    this is what i came up with and i feel like its wrong...please help..

    #include<stdio.h>
    #include<math.h>
    double sqrt(double num);//function type

    int main()
    {
    double num,total;
    total = sqrt(4.0 + 7*3);
    printf("\nthe 4th root is %lf", total);
    return 0;
    }
    output:
    the 4th root is 5.000000Press any key to continue

  2. #2
    End Of Line Hammer's Avatar
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    >>total = sqrt(4.0 + 7*3);
    This is

    7*3 = 21
    4 + 21 = 25
    sqrt(25) = 5

    [edit]Obvious typo fixed (thanks ronin)
    When all else fails, read the instructions.
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  3. #3
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    4+21 = 5? Not in my math class.

    whadda bout

    double root4(double argument){ return sqrt(sqrt(argument)); }
    I haven't used a compiler in ages, so please be gentle as I try to reacclimate myself. :P

  4. #4
    C++ Developer XSquared's Avatar
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    What about root( double n, double number ) { return pow( number, 1.0 / n ); }

    Edit:
    Oops. Forgot to use sqrt.
    Naturally I didn't feel inspired enough to read all the links for you, since I already slaved away for long hours under a blistering sun pressing the search button after typing four whole words! - Quzah

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  5. #5
    Pursuing knowledge confuted's Avatar
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    For a bit of math to explain the double square root above, incase you need it...

    sqr(x)=x^(1/2)
    fourth root (x)=x^(1/4)

    ((x^n)^m)=x^(n*m)

    so...

    sqr(sqr(x))=(x^(1/2))^(1/2)=x^(1/4)=fourth root (x)
    Away.

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