i keep getting incompatible pointer types when i try to compile this
i tried adding a "&", didnt help. whats the probelm here?Code:int isascii(int *src) { if( ishtml(src) == 0 ) return 1; return 0; } int ishtml(char *src) { if( ishtmlkeycode(src) == 1 && ishtmltag(src) == 1 ) return 1; return 0; }
You are creating a pointer in isascii() of type int and then passing it, but the next function ishtml() is trying to receive a pointer to char data type. One of those needs to be changed.Originally posted by mart_man00Code:int isascii(int *src) { if( ishtml(src) == 0 ) return 1; return 0; } int ishtml(char *src) { if( ishtmlkeycode(src) == 1 && ishtmltag(src) == 1 ) return 1; return 0; }
The keyboard is the standard device used to cause computer errors!
i thought the only difference in types were there sizes and pointer just point to a start of data(not necessarily something[0] but not something[.5]).
how can it tell the difference? how are types allocated?
thanks
Think of it as the pointer needs to know what it is pointing to so it knows how many byts to look at. For char its 1 byte, for integer, on most systems its 4 bytes. You are right in that fact that a pointer points to the beginning byte location, but its needs to know how big the data type is so it also knows where the second and third element locations are later on.
The keyboard is the standard device used to cause computer errors!
