Why Doesnt This Function Work ??

[Unregistered]

PLEASE TELL ME WHATS WRONG WITH THIS



FUNCTION PROTOTYPE// void argval (int, char*);

FUNCTION CALL// argval(int,char*);

FUNCTION// void argval(int argc, char* argv[])
{

if (argc < 3)
{
printf("usage : p2 input output -m -n \n");
exit (1);
}
if (argc >5)
{
printf("usage : p2 input output -m -u \n");
exit (1);
}
if((strcmp(argv[1],argv[2])==0))
{
printf("test\n");
exit (1);
}



if(argc==4)
{
printf("ok\n");
if(strcmp(argv[3], "-m")==0)
printf("-m\n");
else if (strcmp(argv[3], "-u")==0)
printf("-u\n");
else
{
printf("error invalid flags usage -m -u\n");
exit(1);
}
}

if(argc==5)
{
printf("ok\n");

if(strcmp(argv[3], "-m")==0)
printf("-m\n");
else if (strcmp(argv[3], "-u")==0)
printf("-u\n");
else
{
printf("error invalid flags usage -m -u\n");
exit(1);
}
if(strcmp(argv[3],argv[4])==0)
printf("test1\n");
else
{
if(strcmp(argv[4],"-m")==0)
printf("-m\n");
else if (strcmp(argv[4], "-u")==0)
printf("-u\n");
else
{
printf("error\n");
exit(1);
}
}
}

if((finp=fopen(argv[1],"r"))==NULL)
{
printf("error\n");
exit(1);
}

if((foutp=fopen(argv[2],"w"))==NULL)
{
printf("error\n");

exit(1);
}
return;

}

[quzah]

What's the point of the extra flags?

if( argc != 5 ) {
   exit ( puts( "Invalid command line."
   "Usage: myprog.exe infile outfile -m -u" ) );
}

if( (infile=fopen( argv[1], "r" )) == NULL )
{
   exit( perror( "Invalid input file." ) );
}
if( (outfile=fopen( argv[2], "w" )) == NULL )
{
   exit( perror( "Unable to create output file." ) );
}
if( strcmp( argv[3], "-w" ) || strcmp( argv[4], "-u" )
{
   exit ( puts( "Invalid command line."
   "Usage: myprog.exe infile outfile -m -u" ) );
}

Quzah.

[The V.]

Well, first off, your prototype is wrong. char* and char*[] are not the same thing (char*[] is really char **). So you need to change that, for sure.

How, exactly, is it called? Does the call look like this:

int main(int argc, char *argv[]){
	argval(argc,argv);
	return 0;
}

The above, BTW, is the correct way to call.