Arrays

[mycron1]

I’m creating a tic tac toe game and would like to use one character array to hold the X”s & O’s, and another int array to hold all the possible winning combinations.
For example:
int LINES[] [] = {
{0, 1, 2},
{3, 4, 5},
{6, 7, 8},
{0, 3, 6},
{1, 4, 7},
{2, 5, 8},
{0, 4, 8},
{2, 4, 6}};

How can I check the contents of the character array against the numeric combinations found in the int array ?

[quzah]

I'd probably just make it a macro, because I like macros...

#define CA0(xo) \
    ( \
        ( BOARD[0] == BOARD[1] == BOARD[2] ) && BOARD[0] == (xo)
    )
#define CA1(xo) \
    ( \
        ( BOARD[3] == BOARD[4] == BOARD[5] ) && BOARD[3] == (xo)
    )
#define CA2(xo) \
    ( \
        ( BOARD[3] == BOARD[4] == BOARD[5] ) && BOARD[3] == (xo)
    )
#define ACROSS(xo) \
    ( CA0(xo) || CA1(xo) || CA2(xo) )

That'll get you started. I personally wouldn't bother using a lookup table like you've got. I suppose it's a nifty way to do it, but we don't really need one.

if( ACROSS( 'x' ) || DOWN( 'x' ) || DIAG( 'x' ) )
    printf("'x' wins!\n");

Quzah.

[RoshanX]

In the code that you have posted,

#define CA0(xo) \
    ( \
        ( BOARD[0] == BOARD[1] == BOARD[2] ) && BOARD[0] == (xo)
    )
#define CA1(xo) \
    ( \
        ( BOARD[3] == BOARD[4] == BOARD[5] ) && BOARD[3] == (xo)
    )
#define CA2(xo) \
    ( \
        ( BOARD[3] == BOARD[4] == BOARD[5] ) && BOARD[3] == (xo)
    )
#define ACROSS(xo) \
    ( CA0(xo) || CA1(xo) || CA2(xo) )

The final #define, is to check the diagonals of the board. I can't understand how that statment works. (if it checks diagonals). And there is a typo error in #define CA2(x0) . It should be

 #define CA2(xo) \
     ( \
        ( BOARD[6] == BOARD[7] == BOARD[8] ) && BOARD[6] == (xo)
)