Thread: getting numbers in an array

I have this code below that accepts up to 8 numbers and stores them in an array. I use a zero to stop taking numbers. I am trying to keep the zero from being stored in the array. Is there a way to do it?

Code:

    printf("\nPlease enter up to 8 numbers to stop entering numbers enter zero\n");
    printf("\n");
    for (i=0;i<8;i++)
    {
        fgets(theNums[i],50, stdin);

		j=strlen(theNums[i])-1;

		theNums[i][j] = '\0';

        if (theNums[i][0]=='0') /*exit if zero*/
            break;
        else
        nums[i]=atoi(theNums[i]);
        numberCount ++; /*count numbers being entered*/
    }
    printf("\n\n");

How do I clear out the spot in the array? I don't know how to do that. Clearing the spot in the array seems like the easier way since I could just put it before the line that has break in it.

cool I will check out memset .... thanks for the help

I tried adding

Code:

theNums[i][j] = '\0';

I still can't get it to work

I have this but it still seems to store the zero in the array

Code:

    printf("\nPlease enter up to 8 numbers to stop entering numbers enter zero\n");
    printf("\n");
    for (i=0;i<8;i++)
    {
        fgets(theNums[i],50, stdin);

		j=strlen(theNums[i])-1;

		theNums[i][j] = '\0';

        if (theNums[i][0]=='0') /*exit if zero*/
		{
            break;
		}
        else
		{
        nums[i]=atoi(theNums[i]);
        numberCount ++; /*count numbers being entered*/
		}
    }
    printf("\n\n");