Help understanding function header

I don't fully understand the following line:

<code>
------------------
int AEEClsCreateInstance(AEECLSID ClsId,IShell * pIShell,IModule * po,void ** ppObj)
{some code}

--------------------
</code>

What does the "void **ppobj" argument mean?

Thanks.

It's a double pointer (pointer to a pointer) of an undefined type (could be anything).

Originally posted by Magos
It's a double pointer (pointer to a pointer) of an undefined type (could be anything).

I don't know what you mean by undefined type. It is clearly a pointer to the type void *. void is a type, it is an incomplete type which cannot be completed, which implies that one cannot apply sizeof to it, the type void still has a utility, one casts the value returned by a function as void when we want to discard the value returned by it. For eg., a typical use might be

Code:

(void) printf("Hello World");

ppobj is a pointer to void *. void * is a an object type. Pointer to any object type can be converted to void * and back again without any loss of information which makes it valuable as a generic pointer.

Thanks to both of you. What you wrote lead me to a section in a book about multiple indirection and void * pointers.

It's c++ book but "a void pointer can be assigned to any type of pointer without the use of a type cast."

and
"The most common use of void * is as a function return type."

Again. thanks.