Thread: help on making a box of size n

I have a problem...i have to make a box of size n, where the box would roughly look like this: **** for n = 4
* *
* *
****

heres what i have so far: i have a "c" shaped one, i cant get the right vertical side...please help

//////////////////////////////////////////////////////////////////

#include <stdio.h>

int
main(void)
{

int i, j; /* loop control variables */
printf("type number of rows\n");
scanf("%d", &j);


for (i = 0; i < j; i++)
printf ("*");
printf("\n");


for (i = 0; i < j - 2; i++)
printf("*\n");



for (i = 0; i < j; i++)
printf ("*");

printf("\n");



return (0);
}

yea...i got the logic, but where i got stuck is how do i print out blank characters for n-2?
i have no idea how to write the code for the middle part of the box...

okay, i got the box to close, but what is wrong with my code where i can't loop the middle part n-2 times? i cant seem to find out whats wrong. thank you

Code:

#include <stdio.h>
 
int
main(void)
{		
		
        int i, j;   /* loop control variables */
        printf("type number of rows\n");      /* prints column labels */
		scanf("%d", &j);
		
		
		for (i = 0; i < j; i++)
			printf ("*");
		printf("\n");
		
		
			
			
		for (i = 0; i < j - 2; i++)
		{
			printf("*");
			for (i = 0; i < j - 2; i++)
				printf(" ");
			printf("*\n");
			}
		
		
		
		
		for (i = 0; i < j; i++)
			printf ("*");
		
		printf("\n");
        
	
              
        return (0);
}