so confused and frustrated

Here is what I am doing. I have posted this a few times over the last few days and you guys have been great with help but I am just getting so frustrated.

I am building an array that will take up to 10 numbers. If a user enters a zero I want to exit and stop taking numbers. If a user enters a letter I want to ignore it and ask for the next number. After the user enters all the numbers I want to give them the sum. I just can't make this work. I have made so many changes and tried so many things and yet I am getting more frustrated.

Code:

 #include <stdio.h> 
 #include <stdlib.h> 
 #include <string.h>
 #include <ctype.h>
 
 #define SIZE 10 /* size of array */
 
 
 int verify (char* value) /* this function will verify the input is a number*/
 {
   int iChars = strlen (value);
   int i;
 
   for (i=0; i<iChars; i++) {
     if (! isdigit (value [i])) {
       return 0; /*Not a number*/
     }
   return 1; /*Is a number*/
   }
 }
 
 
 int main()
 {
    int i, arr, sum, average;
    char temp[50];
 
    /* get the numbers */
    printf("Enter up to 10 numbers, to stop entering numbers enter a zero. \n");
    for(i=0; i<SIZE; )
    {
       if(fgets(temp, sizeof(temp), stdin) == NULL) /*make sure there has been input*/
       {
          printf("Please enter a valid number\n");
          return 1;
       }
 
       if(!verify(temp))
       {
          printf("Invalid input, please try again\n");
       }
       else
       {
          arr[i] = atoi(temp); /*convert char to int */
           if (!arr[i]) {
             break;
           }
          ++i; /* next number */
       }
    }
    return 0;
 }

So what part exactly can't you do?

Quzah.

What about something like

Code:

#include <stdio.h>
#include <string.h>

int main(void)
{
  char theNums[10][50];
  int nums[10];
  int i, j, sum = 0; 
	
  for(i=0; i < 10; i++)
  {
    printf("Enter up to 10 numbers or 0 to quit: ");
    fgets(theNums[i], 50, stdin);
		
    j = strlen(theNums[i])-1;
		
    theNums[i][j] = '\0'; /* get rid of '\n' */
		
    if(theNums[i][0] == '0')
      break;
  else if(!isdigit(theNums[i][0]))
  {
    printf("%s is not a valid entry.\n", theNums[i]);
    nums[i] = 0;
  }
  else		
    nums[i] = atoi(theNums[i]);
  }
	
  printf("\n\n");
	
  for(j=0; j < i; j++)
    sum+=nums[j];

  printf("The sum of your numbers is %d", sum);
	
  return 0;
}

Of course, you'd have to expand the test for valid digits beyond theNums[i][0] as a user could enter 2dfgt or something.

I wonder if this would work.... or if it's valid... hmm