fscanf() question

Hi,

First my code:

Code:

#include <stdio.h>

main()
{
      FILE *stream;
      char dude[7];
      int w;
      stream = fopen( "C:\\bestand.dat", "r" );

      while( !feof( stream ))
           {
           fscanf( stream, "%s", dude );
           printf("%s ", dude );
           }

      fclose( stream );

      getche();
}

bestand.dat contains the text

Schrijven in een data bestand

Now, my question,
the word 'Schrijven' contains 10 characters \0 included.
But i only declared dude[7], so basically 'Schrijven' wont fit into the variable dude.

Is this because fscanf ( like scanf ) doenst check the buffer so an buffer overflow can occur?
Just to make something clear


Thanks for your time

Encrypted

Function fscanf() is one of those functions permitting overflows.

Ok man

Thank You

Graag gedaan.

Cool,

Nederlanders

Laat ik erg nog een vraagje achter plakken:

functies zoals getch, getche en getchar zijn toch allemaal wel ANSI-C?

Dit omdat gcc de functie getch(e) niet herkent...

English:

Another question:

functions like getch, getche en getchar are all ANSI-C right?

this because gcc doesnt reconize them........

Thanks again

No they r not standard functions.. They r usually available in he headr conio.h which is not standard either...

Jazeker, Nederlanders. Er zijn er nog wel een paar, Travis Dane bijvoorbeeld.

>functions like getch, getche en getchar are all ANSI-C right?

Of those functions mentioned, only getchar() appears in my copy of the ANSI C standard. So I think the others are not standard. But there is another function, getc() which is.

#include <stdio.h>
int getc(FILE *stream);

#include <stdio.h>
int getchar(void);

The getchar function is equivalent to getc with the argument stdin.