Thread: arrays with malloc

How do I create dynamically arrays using malloc???

In C++ it's :

int count;
count=40;

char *array;
array=new array[count];


but how it is in C????

Thank you in advance!

For a 2d array:

Code:

#include<stdio.h>
#include<stdlib.h>

int main()
{
	char **iptr = (char **) malloc (sizeof(char*) * 3);
	for(int i = 0;i < 3; i++)
		iptr[i] = (char *) malloc (sizeof(char) * 10);

	strcpy(iptr[0], "Chicken");
	strcpy(iptr[1], "Cow");

	printf("%s  %s", iptr[0],iptr[1]);
                    for(i=0;i<3;i++)
                               free(iptr[i]);
	return 0;
}

The format is off because I cut and pasted part of it and than tried to type other parts.

For a normal array

Code:

char *array = (char *) malloc (sizeof(char) * 20);

The array is the same as
char array[20];

Thank you a lot Troll_King!!! It worked!!!!!!