Thread: decreasing variable

How about finding a way to "remember" the numbers you've already generated...

Also, you'll want to get numbers between 1 and 50 (or whatever), I guess, so different method of getting random numbers is needed. That way, you won't need to check for 0.

[edit]
Also, there's various examples of this on the forums here, try a search and see what you can find.

Oopps, sorry, I didn't see it was rando(), I thought it was rand(), hence my comments.

If your own version (rando) gives you 0 - 49, and you don't want 0, why not fix it so it gives you 1 - 49.

>with this for statement i want to start a loop that generates 6 random and different numbers.
Your loop is a bit unusual:

>if (a == a && a == 0)
Of course a is going to be equal to a, you can remove that and just test for 0. Though since you want all different numbers simply testing for 0 doesn't help you much.

Perhaps if you kept a record of the numbers already produced and didn't increment the counter until a new number is found:

Code:

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

static int is_saved ( int val, int *saved, int size )
{
  int i;

  for ( i = 0; i < size; i++) {
    if ( saved[i] == val ) {
      return 1;
    }
  }

  return 0;
}

int main ( void )
{
  int a, i = 0;
  int saved[6];

  srand ( (unsigned)time ( NULL ) );

  while ( i < 6 ) {
    a = rand() % 50;

    if ( !is_saved ( a, saved, 6 ) ) {
      saved[i++] = a;
    }
  }

  printf ( "Your numbers are: " );

  for ( i = 0; i < 6; i++ ) {
    printf ( "%d ", saved[i] );
  }

  printf ( "Your bonus number is: %d\n", rand() % 50 );

  return 0;
}

-Prelude