Filling an array in a structure

This is a discussion on Filling an array in a structure within the C Programming forums, part of the General Programming Boards category; This is probally a newbie question (shocking becuase im a newbie) but ive looked in my C book, with google, ...

  1. #1
    Registered User
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    Oct 2002
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    4

    Filling an array in a structure

    This is probally a newbie question (shocking becuase im a newbie) but ive looked in my C book, with google, everything, and I can't find it.

    My question is, how do you fill an array thats in a structure? in other words, i have a structure that i pass through all my functions, and in that structure is an array (int teamstats[5][18).
    I want to fill that array on the load of the program with the following data:

    int teamstats[][18] = {
    {99 ,97, 85, 82, 61, 75, 72, 87, 93, 87, 99, 26, 87, 87, 86, 85, 87, 68},

    {94, 96, 84, 81, 65, 85, 28, 86, 85, 97, 87, 94, 78, 95, 76, 90, 87, 68},

    {93, 95, 83, 80, 60, 87, 68, 97, 95, 75, 86, 89, 96, 78, 85, 78, 87, 68},

    {99, 99, 88, 77, 66, 96, 93, 64, 75, 86, 97, 86, 82, 89, 76, 81, 87, 68}
    } ;

    but I found i can't declare it like you can with a normal array (aka teamstats[][18] = {"5", "43", "34"....etc.

    im at a lost, any help would be greatly appreciated.
    thanks!

    Code:
    
    struct var 
    {
    int teamstats[5][18];
    };
    
    
    void fill(struct var *);
    
    
    void main(void)
    {
    struct var global;
    
    flil(&global);
    }
    
    void fill(struct var *global)
    {
    
    /* put code here to fill array with this data:
    
    {99 ,97, 85, 82, 61, 75, 72, 87, 93, 87, 99, 26, 87, 87, 86, 85, 87, 68}, 
    
    {94, 96, 84, 81, 65, 85, 28, 86, 85, 97, 87, 94, 78, 95, 76, 90, 87, 68}, 
    
    {93, 95, 83, 80, 60, 87, 68, 97, 95, 75, 86, 89, 96, 78, 85, 78, 87, 68}, 
    
    {99, 99, 88, 77, 66, 96, 93, 64, 75, 86, 97, 86, 82, 89, 76, 81, 87, 68}
    
    */
    
    }

  2. #2
    ATH0 quzah's Avatar
    Join Date
    Oct 2001
    Posts
    14,826
    You can only initialize an array like that (using the braces) at the time the variable is created, on the same line the variable is created on. IE:
    Code:
    struct mystruct
    {
        char c;
        int array[3];
    };
    
    Then you'd do:
    
    struct mystruct x = { 'a', { 1, 2, 3 } };
    Or, if you're assigning them individually:

    x.array[1] = 23445;

    Through a pointer:

    struct mystruct *ptr;
    ptr = &x;

    prt->array[0] = 30;


    Quzah.
    Hope is the first step on the road to disappointment.

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