A beginner's problem

I am getting the syntax error message " ; before type char". I have searched high and low for a missing ";" but everything seems to be in the proper place. It is the last error in my program before a successful compilation.

Please Help!

Thanks!

Show us the code (using [code] tage (see my signature). Also what line is it giving the error on?

Ummm okay let me use my telepaty powers to c ur code throught ur mind !!!!! Post the code if u need a decent reply nun of use is harry porter u c

It's just a hunch, but see if this is what's wrong

Code:

---


#include <stdio.h>

int main(void)
{
    int i;
   
    i = 2;
           
    printf("%d times %d is %d", i, i, i * i);
       
    //  uncomment int l = 6 and recompile as is
       
    //  int l = 6;
       
    // Trying to create a variable here caused: 'syntax error : missing ';' before 'type'
                       
    // then try moving int l to the top and try it again.
       
       
    return 0;
}

---

Maybe that's it.

Thanks guys, my code was this:

void listrecords()
{fileptr=fopen("a:hospital", "r");
char option;
readfile();
.......

It finally dawned on me that my variables had to be declared first before opening the file. DUH!

Now my output has some garbage in it (not from the above problem) I will try to solve that problem tonight. I just stumbled on this board - it is great to know there are people out there who are willing to hear the drivel of a newbie.

Thanks!

The problem is you're trying to use C++ variable declaration in C.

int x = 1;
printf("%d", x );

The above is valid C code. The below is valid C++ code, and is not valid C code:

int x = 1;
printf("%d", x );
int y;

In C, all variable declaration must be at the beginning of the scope block.

Quzah.