my instructor wants us to write a encryption program and gave us the following code. I know what it does, but what i would like to know is how does it work?would some explain it?
btw, does '\b' mean a [space]?Code:void getMessage(char*p){ char*s = p; printf("Enter a message to be encryptes -> "); while((*s=getch())!="\n"){ if(*s == '\b'){ s--; s=(s<p) ? p : (printf("\b \b"),s); } else { printf("*"); s++; } } *s='\0\; }
many thanks to any help!
Last edited by lucy; 10-10-2001 at 07:52 PM.
uh... there's a frowny face in your code man ):
opps the face was an accident
That frowny face is what happens when you do :( in code. I really wish code would disable smileys...
'\b' is the standard character for backspace.
So, pretty much what the program does is it takes the pointer and if the user types in something not a backspace, then it stores it in the string, advances the pointer, and prints a '*'.
If the user does type in a backspace, it decrements s, checks to see if this would be a buffer underflow (s < p)? and if it is, then it just keeps s pointing to the beginning of the buffer (s = p), and otherwise it actually keeps s decremented, and prints a backspace character (ie, gobbles up one of the '*'s).
