Found 'if' expecting ')'

Can somebody help me to debug this. And if you can explain me why is this happening? Thanks

Code:

/* PRINT_IT.C-This program prints a listing with line numbers! */
 #include <ansi_c.h>
 #include <stdio.h>

 void do_heading ( char *filename);

 int line, page;

 main ( int argv, char *argc[] )
 {
     char buffer[256];
     FILE *fp;

     if( argv < 2 )
     {
           printf( "\nProper Usage is: " );
           printf(   "\n\nPRINT_IT filename.ext\n" );
           exit (1);
     }

     if(( fp = fopen ( argc[1], "r"  )) ==NULL)
     {
           printf (   "Error opening file, %s!" ,argc[1] );
           exit(1);
     }

     page = 0;
     line = 1;
     do_heading ( argc[1] );

     while ( fgets( buffer, 256, fp ) != NULL
      
           if (line % 55 ==0)
     {          do_heading ( argc[1] );

           printf ( "%4d:\t%s", line++, buffer);
     }

     printf (   "\f");
     fclose (fp);
     return 0;
 }

 void do_heading ( char *filename )
 {
     page++;

     if (page > 1)

code tags added by Hammer

while ( fgets( buffer, 256, fp ) != NULL)

yes, monster is right. remember, when using parenthesis (sp?) you must always have a mental "mirror" of them (as well as '{' and '}') and there should be an even number of them in the line/code.

Found 'if' expecting ')'

Not that hard to understand, imo.
Remember that the compiler often reports the error one line below the actual error.

Originally posted by Sang-drax
Not that hard to understand, imo.
Remember that the compiler often reports the error one line below the actual error.

because it actually reports the error when it sees the next thing, and its not what it was looking for (the parenthesis in this case)

Originally posted by Monster
while ( fgets( buffer, 256, fp ) != NULL)

Thanks a lot! I think this is more often happening when people copy source codes from somewhere than when they write it themselves (as I did).