Found 'if' expecting ')'

Can somebody help me to debug this. And if you can explain me why is this happening? Thanks

Code:

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/* PRINT_IT.C-This program prints a listing with line numbers! */
 #include <ansi_c.h>
 #include <stdio.h>

 void do_heading ( char *filename);

 int line, page;

 main ( int argv, char *argc[] )
 {
    char buffer[256];
    FILE *fp;

    if( argv < 2 )
    {
          printf( "\nProper Usage is: " );
          printf(  "\n\nPRINT_IT filename.ext\n" );
          exit (1);
    }

    if(( fp = fopen ( argc[1], "r"  )) ==NULL)
    {
          printf (  "Error opening file, %s!" ,argc[1] );
          exit(1);
    }

    page = 0;
    line = 1;
    do_heading ( argc[1] );

    while ( fgets( buffer, 256, fp ) != NULL
     
          if (line % 55 ==0)
    {          do_heading ( argc[1] );

          printf ( "%4d:\t%s", line++, buffer);
    }

    printf (  "\f");
    fclose (fp);
    return 0;
 }

 void do_heading ( char *filename )
 {
    page++;

    if (page > 1)

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code tags added by Hammer

while ( fgets( buffer, 256, fp ) != NULL)

yes, monster is right. remember, when using parenthesis (sp?) you must always have a mental "mirror" of them (as well as '{' and '}') and there should be an even number of them in the line/code.

Quote:

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Found 'if' expecting ')'

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Not that hard to understand, imo. :rolleyes:
Remember that the compiler often reports the error one line below the actual error.

Quote:

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Originally posted by Sang-drax
Not that hard to understand, imo. :rolleyes:
Remember that the compiler often reports the error one line below the actual error.

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because it actually reports the error when it sees the next thing, and its not what it was looking for (the parenthesis in this case)

Quote:

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Originally posted by Monster
while ( fgets( buffer, 256, fp ) != NULL)

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:D
Thanks a lot! I think this is more often happening when people copy source codes from somewhere than when they write it themselves (as I did).