Thread: Help Me!

Code:

#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>

#define SIZE 4

int main()
{
char a[SIZE];
char *ptrA=a;
int c[SIZE];
int count;
int sum;
int first,second,third,fourth;
int varify=1;

while(varify==1)
{
//get nums
	printf("Enter Number for Array\n");
	
	for(count=0;count<SIZE;count++)
	{
		scanf("%d",&a[count]);
	}
//convert to ints
	for(count=0;count<SIZE;count++)
	{
		c[count]=atoi(ptrA);
	}
//checking
	for(count=0;count<SIZE;count++)
	{
		if(isdigit(c[count])==1)
		{
			printf("Must A Numeric Value");
			varify=1;
		}
		else
		{
			varify=0;
		}
	}
}


//printing
	printf("Input Reads:\n");
	
	for(count=0;count<SIZE;count++)
	{
		
		printf("%d\n",a[count]);
	}

//adding
	printf("Summing Numbers\n");
	
	first=a[0];
	second=a[1];
	third=a[2];
	fourth=a[3];
		
//printing
	sum=first+second+third+fourth;
	printf("Sum is: %d\n",sum);

}

This runs but then errors once it is finished! I dont know why.
Thanx!

Stop double posting. Yes, the code is slightly different between your other post and this, but since the bulk of the application is the same, you shouldn't be spamming the board with posts.

Quzah.

What errors?

Could be this, since you try to print a char as an int.
printf("%d\n",a[count]);

I already told you why atoi doesn't work right. BECAUSE YOU ARE USING SCANF WRONG! You are not scanning strings of digits, you are scanning an integer. Period.

[edit]
char buf[BUFSIZ];
int x;
scanf("%s", buf );
x = atoi( buf );

That is how you read a string of numbers and convert it with atoi. What you're doing is scanning INTEGERS into a character array, and then you're trying to treat the array of characers as a string.

Example: I input: 10 20 30 40

You try running atoi() on that "string", and get: <character whose desimal value is 10, character whose decimal value is 20, characer whose decimal value is 30, character whose decimal value is 40> and you're expecting that to turn out to be "real" integers. Sorry, but that's not how it works.
[/edit]

Quzah.