Very Simple C Program

This is a discussion on Very Simple C Program within the C Programming forums, part of the General Programming Boards category; Hi I know this is really simple but i've been stuck trying to work this out for a couple of ...

  1. #1
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    Red face Very Simple C Program

    Hi

    I know this is really simple but i've been stuck trying to work this out for a couple of days now.

    I need to write a simple c program in which you can enter three numbers, in any order, and the resulting output will put them in ascending order.

    I think IF statements or arrays might be needed???

    If any one can give me a hand i'd really appreciate it.

  2. #2
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    Post the code you have so far and then someone can probably nudge you in the right direction.
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  3. #3
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    Here you go...
    Code:
    #include <stdio.h>
    
    #define RANGE 3
    
    int main(
            int argc,
            int *argv[]
            )
    {
      int numbers[RANGE], ctr, a, b;
    
    /*
    ** Read in the numbers ( limit set using RANGE definition above )
    */
      for( ctr=0 ; ctr < RANGE ; ctr++ )
      {
        printf( "\nEnter next number: " );
        /** You would normally check for non integers **/
        /** before this next statement **/
        scanf( "%d", &numbers[ctr] );
      }
    
    /*
    ** Sort the array
    */
      for( ctr=0 ; ctr < RANGE ; ctr++ )
      {
        if( numbers[ctr] < numbers[ctr+1] )
        {
          /** If the current number is less than the next number, **/
          /** swap them round and start again **/
          /** I think this is known as a bubble sort **/
          a = numbers[ctr];
          b = numbers[ctr+1];
          numbers[ctr] = b;
          numbers[ctr+1] = a;
    
          ctr = -1; /** Effectively restarts loop **/
                    /** ( -1 because loop executes ctr++ ) **/
        }
      }
    
    /*
    ** Print array
    */
      printf( "\nNumbers in sorted order:\n\n" );
    
      for( ctr=0 ; ctr < RANGE ; ctr++ )
      {
        printf( "%d\n", numbers[ctr] );
      }
    
      printf( "\n" );
    
      return( 0 );
    }

    &#91;code]&#91;/code]tagged by Salem

  4. #4
    End Of Line Hammer's Avatar
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    >>I think this is known as a bubble sort
    It is, but you've implemented it incorrectly, and caused a nasty little bug

    The problem is here:
    >>for( ctr=0 ; ctr < RANGE ; ctr++ )
    >>if( numbers[ctr] < numbers[ctr+1] )
    Assuming RANGE is 3:
    when ctr is 2, the if statement will check numbers[2] against numbers[3]. See the problem? I'll leave that one for you to ponder over....
    When all else fails, read the instructions.
    If you're posting code, use code tags: [code] /* insert code here */ [/code]

  5. #5
    Registered User datainjector's Avatar
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    Yeah as hammer said its bubble sort try this
    Code:
    void sort( char s [] )
    {
             int cnt_main, cnt_sub;
             int hold;
              hold =0;
             
              for ( cnt_main =0; cnt_main <= SIZEofarray-1; cnt_main++)
                             for( cnt_sub = 0; cnt_sub <= SIZEofarray-2;cnt_sub++ )
                                       if ( s[i] > s[i+1] ){
                                               hold = s[i];
                                               s[i] = s[i+1];
                                               s[i+1] = hold;
                                       }
    }
    Ahh well if u guys do find a mistake or anything well i am alil tipsy at the movement ...ahh well just rty it ... or u can try quit sort which is faster than bubble..
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