Why this do-while loop doesn't work as I expected?

I just started writing this program... There will be more code inside main, but it already doesn't work as I expected it to...
What it does is: it runs correctly once, and then after execution it runs again, but without stopping for user input? Did I do something wrong???

Code:

int main()
{


	char again = 'y';
	char inputstring[512] = "One, two, three.";
	char *inputptr;
	inputptr = inputstring;
	
	
	
	do
	{
		{
		printf("Enter an English text. Use no more than 511 characters, including white spaces.\n");
		gets(inputstring);
		printf("The text you entered was: ");
		printf(inputstring);


		}






	printf("\nWould you like to enter another text?");
	again = getchar();

	}
	while (again == 'y' || again =='Y');

}

Thanks...

Thanks a lot, every single time I'm learning something new here...

accordingly to your prog.

why not ...

char again ='Y';

do {
..
..
..
..
} while (toupper(again) == 'Y' );

>> more faster coding.

The statement:

if( x == 'a' || x == 'A' )

Is more than likely as fast, if not faster, than the following statement:

if( toupper( x ) == 'A' )

The reason being, the first test does at most two comparisions. The second does one comparision, but has the overhead of either processing a macro (ie: a math operation in changing x to an upper case) or calling a function.

In which case, the first is likely the faster of the two.

Quzah.

I'm not supposed to use anything from <ctype.h>, so... toupper would be out of question anyway...
But thanks.