i was reading a tutorial in c and i found this...
what do he mean by... looking at the memory location..... how would i do that...? how can i find out if the values are really hellow \0?Code:main() { /* copy "hello" into str1. If str1 isn't big enough, hard luck */ strcpy(str1,"hello"); /* if you looked at memory location str1 you'd see these byte values: 'h','e','l','l','o','\0' */
Only the strong survives.
You can print out individual characters.
Code:int main() { int i; for ( i = 0; i < strlen(str1); i++ ) printf( "str1[%d] is %c", i, str1[i] ); }
As an extension to Nutshells, you can hex dump the array:
Code:#include <stdio.h> #include <ctype.h> #define ARRAY_SIZE 20 int main(void) { char my_string[ARRAY_SIZE] = "hello"; int i; for (i = 0; i < ARRAY_SIZE; i++) { printf ("%02x(%c) ", my_string[i], (isprint(my_string[i])?my_string[i]: ' ')); if ((i+1) % 10 == 0) putchar ('\n'); } return 0; } /* Output: 68(h) 65(e) 6c(l) 6c(l) 6f(o) 00( ) 00( ) 00( ) 00( ) 00( ) 00( ) 00( ) 00( ) 00( ) 00( ) 00( ) 00( ) 00( ) 00( ) 00( ) */
When all else fails, read the instructions.
If you're posting code, use code tags: [code] /* insert code here */ [/code]
if you want the memory location, you can do the following:
if you want to see the values in the array and you have a robust IDE, you can run the debugger and see the values in the array.Code:printf( "%p", &str );
