verify EOF

hi

please have a look at the following code.

Code:

---

#include<stdio.h>
#include<conio.h>

main ()
{
        int c;

  while((c=getchar()) !=EOF)
          putchar(c);
  getch();
}

---

how do i verify that the expression getchar() !=EOF is zero or one?
AND :D how do i print the value of EOF?

threadhead

>how do i verify that the expression getchar() !=EOF is zero or one?
If putchar ( c ); executes then the expression is one. You can say something like this, though that would be a bit silly:

Code:

---

int chk_bool = ( ( c = getchar() ) != EOF );

while ( chk_bool != 0 ) {
  putchar ( c );
  chk_bool = ( ( c = getchar() ) != EOF );
}

---

>how do i print the value of EOF?

Code:

---

#include <stdio.h>

int main ( void )
{
  printf ( "%d\n", EOF );

  return 0;
}

---

Though once again, there's little point in doing this.

-Prelude