Thread: repeat number program

Can someone help me with how I can re-enter this loop after it breaks from the first repeated number? I need it to display all of the repeated numbers in the integer that the user enters.

Code:

#include <stdio.h>

#define TRUE 1
#define FALSE 0

typedef int Bool;

main(){

Bool digit_seen[10] = {0};

int digit;
long int n;

printf ("Enter a number: ");
scanf("%ld", &n);

while (n > 0){
 digit = n % 10;
 if (digit_seen[digit])
 break;
 digit_seen[digit] = TRUE;
 n /= 10;
}

if(n>0)
printf("The repeated digit(s) are:%3d\n", digit);
else
printf("No Repeat");

return 0;
}

I am posting this because you did not use code tags on this thread. In the furture please use Code Tags. They make your code MUCH easier to read and people will be much more likely to help you if you do. And they'll be happy about helping you


For example:

Without code tags:

for(int i=0;i<5;i++)
{
cout << "No code tags are bad";
}

With Code Tags:

Code:

for(int i=0;i<5;i++)
{
     cout << "This code is easy to read";
}

This is of course a basic example...more complicated code is even easier to read with code tags than without.

I've added code tags for you this time. They can be added by putting [code] at the beginning of your code and [/code] at the end. More information on code tags may be found at the link in my signature. Any further questions or ways I can help please feel free to PM me.


You were close....just use [] instead of <>.

Ah you editted it before I could....very good . Here folks is someone who tries and is smart enough to look things up!

umm i didn't look extremely closely...it's well past the time that i should be asleep so I'm a bit blury eyed but I would try a nested loop. That's when you put one loop inside another. So put an outer while loop that has conditions that make it so it repeats as much as you want....Hope this helps...I'm off to bed.

Oh, and no prob on the code tags, happens all the time, and many people don't make the effort to do it at all on their first post, thanks.