Convert Phone Letters To Numbers

This is a discussion on Convert Phone Letters To Numbers within the C Programming forums, part of the General Programming Boards category; iI am a new C programmer and I am trying to write a program that will convert the letters of ...

  1. #1
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    Convert Phone Letters To Numbers

    iI am a new C programmer and I am trying to write a program that will convert the letters of a phone number such as 1-800-collect into the correct numbers. Could someone help me get this started. I'm not too sure how to turn my getchar() into a number.

  2. #2
    Registered User red_baron's Avatar
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    you could check to see first what letter the first character is for example A,B, and C are all 2 so if the first character is A,B, or C, input a 2 into a seperate int variable, and for teh second letter you would do the same thing, etc


    ABC=2
    DEF=3
    GHI=4
    JKL=5
    MNO=6
    PRS=7
    TUV=8
    WXY=9
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  3. #3
    Just Lurking Dave_Sinkula's Avatar
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    The function strchr() scans a string for the first occurrence of a given character; strchr() returns a pointer to the first occurrence of the character c in s; if c does not occur in s, strchr returns null. This could be used for something like the following.

    Code:
    #include <stdio.h>
    #include <string.h>
    
    char Digit(char ptr)
    {
       if(strchr("ABCabc", ptr))        return('2');
       else if(strchr("DEFdef", ptr))   return('3');
       else if(strchr("GHIghi", ptr))   return('4');
       else if(strchr("JKLjkl", ptr))   return('5');
       else if(strchr("MNOmno", ptr))   return('6');
       else if(strchr("PQRSpqrs", ptr)) return('7');
       else if(strchr("TUVtuv", ptr))   return('8');
       else if(strchr("WXYZwxyz", ptr)) return('9');
       return(ptr);
    }
    
    int main(void)
    {
       const char number[] = "1-800-COLLECT", *ptr;
       puts(number);
       for(ptr = number; *ptr; ++ptr)
       {
          putchar(Digit(*ptr));
       }
       return(0);
    }
    
    /* my output
    1-800-COLLECT
    1-800-2655328
    */
    Another way might be as follows.
    Code:
    #include <stdio.h>
    #include <string.h>
    
    char Digit(char ptr)
    {
       const char *Letter[] =
       {
          /* 2 */"ABCabc",
          /* 3 */"DEFdef",
          /* 4 */"GHIghi",
          /* 5 */"JKLjkl",
          /* 6 */"MNOmno",
          /* 7 */"PQRSpqrs",
          /* 8 */"TUVtuv",
          /* 9 */"WXYZwxyz",
       };
       size_t i;
       for(i = 0; i < sizeof(Letter)/sizeof(*Letter); ++i)
       {
          if(strchr(Letter[i], ptr))
             return(i + '2');
       }
       return(ptr);
    }
    
    int main(void)
    {
       const char number[] = "1-800-COLLECT", *ptr;
       puts(number);
       for(ptr = number; *ptr; ++ptr)
       {
          putchar(Digit(*ptr));
       }
       return(0);
    }
    
    /* my output
    1-800-COLLECT
    1-800-2655328
    */

  4. #4
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    This is the code that I have come up with so far. Can anyone help me out as to why it is not converting my getchar() statement into a letter

    Code:
    #include <stdio.h>
    
    main(){
    
    char ch;
    int i;
    
    printf ("Enter a phone number: ");
    while ((ch = getchar()) != '\n');
    
    i = ch;
    
    if ('a' <= ch && ch <= 'c')
     i = 2;
    if ('d' <= ch && ch <= 'f')
     i = 3;
    if ('g' <= ch && ch <= 'i')
     i = 4;
    if ('j' <= ch && ch <= 'l')
     i = 5;
    if ('m' <= ch && ch <= 'o')
     i = 6;
    if ('p' <= ch && ch <= 's')
     i = 7;
    if ('t' <= ch && ch <= 'v')
     i = 8;
    if ('w' <= ch && ch <= 'y')
     i = 9;
    
    printf ("%d", i);
    
    return 0;
    }
    &#91;code]&#91;/code]tagged by Salem

  5. #5
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    Thanks for your help Salem!

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