Converting Float to Integer

[Dum-E]

I am really new to programming and am trying to modify an existing program, what I would like to know is if it is possible to convert a floating point number to a whole integer number. For example if I have 123.456 I want to convert it to 123456. I have seen some examples where they simply round the float up or down, but this will not work for me. I need the whole number but basically without any decimal point.

Any help appreciated.

[KingoftheWorld]

First you should convert the float number to
a string.(numbers to characters) then
you can store it in an array, then
parse it (eg. using loop) to find where is the
decimal point(.)locate, then start count how
many number after the decimal point. Finally
if there ,for example, 3 numbers after decimal point then multiply the float number by 1000.
if 2 numbers after decimal point then multiply
the float number by 100, and so on....
Hope you got an idea. There are several way
of algorithms to deal with it.

KingoftheWorld

[Monster]

Working with floats is very fuzzy. For example a float with value 123.456 can be stored in memory like 123.4559999998. That's the reason why you should never compare floats. You can get the same problem when trying to convert a float to an integer the way you want to do it.

Here is a small example, but it's very messy and it doesn't always work.

It works fine when I convert the number 123456001, but when I try 123.45601, the result is: 123.456009.

#include <string.h>

int main ()
{
   float a = 123.456001;
   int result = 0;
   char buf[40];
   char *ptr;

   /* copy float number to string (is it %f ???, not sure) */
   sprintf(buf, "%f", a); 

   /* find the dot */
   if((ptr = strchr(buf, '.')) == NULL) return -1; 

   /* remove the dot */
   for(; *ptr != '\0'; ptr++) *ptr = *(ptr+1); 

   /* remove trailing zero's */
   for(ptr-=2; *ptr == '0'; ptr--) *ptr = 0; 

   /* copy string to integer (can also use atoi) */
   sscanf(buf, "%d", &result); 
   printf("%d\n", result);
   
   return 0;
}