Thread: Problems with a while loop

This isn't all the code of a program nor is it finished so its v.likely to not be perfect yet. My problem is with this loop, when the program comes to it, it prints to screen two lots of "choose from the....." and then waits for the input that will get put in &choose.
Any ideas why this would be. Thanks

Code:

while (choose != 'q') {
	printf("Choose from the following set of options:\n");
	printf("Get the (m)edian, (a)verage, or (q)uit?: ");
	scanf("%c",&choose);

//PROBLEM WITH WHILE LOOP ABOVE

   int i;

	switch (choose) {

   	case 'm':
         bubble_srt(ptr, num);
         for (i=0;i<num;i++)
         	printf("ptr[i] = %d",i,ptr[i]);
      	//printf("The median for your set of numbers will be:\n%f",median);
      	break;

		case 'a':
      	for (i=0;i<num;i++) {
         	sum += ptr[i];};
         mean = (sum/num);
			printf("The average for your data set will be:\n%f",mean);
         break;

      default:
      break;
  	}

}

sounds like you have a newline char left in your input buffer. this problem has been dealt with at least 10 times this week alone. Read some more threads or search for the answer.
if you see this .... fflush(stdin) recommended,ignore it. its bad info.













ok i relent.....

while (getchar() != '\n') continue;

This will clear ur input buffer. now u decide where to place it in your code.

Code:

while (choose != 'q') {
   while (getchar() != '\n') {}
	printf("Choose from the following set of options:\n");
	printf("Get the (m)edian, (a)verage, or (q)uit?: ");
	scanf("%c",&choose);

Works, thanks