Variable size arrays

This is a discussion on Variable size arrays within the C Programming forums, part of the General Programming Boards category; Hi all, I'm having trouble with arrays ( Yes I'm new to C ) Here is what I want to ...

  1. #1
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    Variable size arrays

    Hi all, I'm having trouble with arrays ( Yes I'm new to C )

    Here is what I want to do in a nutshell:

    #include <stdio.h>

    main ()
    {
    printf("Please input the size of the array you want");
    int arrsize;
    scanf("%d",&arrsize);
    int myarray [arrsize];
    }

    I can't do that so I've been experimenting with malloc and have come up with this:

    int arrsize;
    scanf("%d",&arrsize);
    int *numptr;
    numptr = (int *) malloc (arrsize);

    This is where I'm stuck, now I've got this chunk of memory ( is it the right size? ) how can I make it so it acts as an array.
    IE

    myarray [0]
    myarray [1]
    ...
    myarray [arrsize]

    Thanks in advance for any help.

  2. #2
    moi
    moi is offline
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    numptr = (int *) malloc (sizeof (int) * arrsize);
    hello, internet!

  3. #3
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    thanks, will I then be able to use that memory space as an array. If so how do I access it?

    I want to add numbers to each each member of the array like this ideally:

    int i;
    for (i=0;i<=arrsize;i++) {
    myarray[i] = i;
    }

    Any ideas

  4. #4
    End Of Line Hammer's Avatar
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    Pointers and dynamic allocation etc

    That's the full details anyways, but there are also plenty of examples on here if you look for them.
    When all else fails, read the instructions.
    If you're posting code, use code tags: [code] /* insert code here */ [/code]

  5. #5
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    Good link thanks, I've sorted my problem now.

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