output from nested while loop

Hi, I'm trying to get the following output from a nested while loop:
enter=5:
1
22
333
4444
55555
I can do this fine with a for loop but cannot get it right with a 'while', and i'm not surewhat i'm doing wrong. The code i've got below outputs:
1
22
33
44
55
66...
Can anybody make a suggestion?? Thankyou

#include <stdio.h>
main()
{
int rows;
int num=1;
int col=1;

printf("\nEnter a number between 1-9\n"); //get values
scanf("%d",&rows);

if (rows > 9||rows < 1)
{
printf("\nSorry. Invalid input.\n");
return; //terminate program
}

while (num<= rows){ //outer loop
printf("%d\n",num);
num++;

while (col<= rows) //inner loop
col++;
printf("%d",num);


}//end while loop
return 0;

}//end main

Quote:

---

while (col<= rows) //inner loop
col++;
printf("%d",num);

---

Without brackets, the while loop only affects the incrementing of cols...
...should be:

Code:

---


while (col<= rows) //inner loop
 {
  col++;
  printf("%d",num);
 }

---

Code:

---

#include <stdio.h>
#include <stdlib.h>

int main ( void )
{
  int i, j, val;
  printf ( "Enter a number from 1 - 9: " );
  /*
  ** Always check the return value of user input functions.
  */
  if ( scanf ( "%d", &val ) != 1 || val < 1 || 9 < val ) {
    fprintf ( stderr, "Invalid input\n" );
    exit ( EXIT_FAILURE );
  }
  /*
  ** Outer loop, determine the number of rows and
  ** the value to be printed, after printing,
  ** move to the next line.
  */
  for ( i = 1; i <= val; i++ ) {
    /*
    ** Inner loop, print the value i times.
    */
    for ( j = 0; j < i; j++ )
      printf ( "%d", i );
    printf ( "\n" );
  }
  return EXIT_SUCCESS;
}

---

-Prelude