loops and arrays

please help with this code.

dont want to see numbers in the array file_nums.


int num_files,file_nums[25],loop;

printf("input amount of files:>");
scanf("%d",&num_files);

for(loop=0;loop<num_files;loop++)
{
scanf("%d",&file_nums[loop];
}

for(num=0;num<fnumber;num++) /* fnumber=3 */
{
int seen=0;

for(loop=0;loop<num;loop++)
{
if(file_nums[loop]==file_nums[num])
{
seen=1;
break;
}

if(!seen) printf("%d",num_files[num]);

}

Too many brackets.

You mean too few. This is the same code formatted as closely as I could figure.

Code:

int num_files, file_nums[25] = '0', loop; 

printf("input amount of files:> "); 
scanf("%d",&num_files); 

for(loop=0;loop<num_files;loop++) 
{ 
    scanf("%d",&file_nums[loop];  /*how do I know what to do?*/
} 

for(num=0;num<fnumber;num++)  /* fnumber=3 */  //fnumber means?
{ 
    int seen=0; 

    for(loop=0;loop<num;loop++) 
    { 
        if(file_nums[loop] == file_nums[num])  /*huh? tell me what's happening here*/
        { 
            seen=1; 
            break; 
        } 
        if(seen != 0)   /* be explicit */ 
            printf("%d",num_files[num]);
    } /*you forgot this bracket*/
}

This is very twisted code, if there's any doubt as to whether or not the reader will understand on the first pass, be sure to comment it. Your loop structure is very hard to follow since each loop's testing condition is based on the counter for the previous loop.

Out of curiosity, what are you trying to do with this code? I can't figure it out.

dude, you are right. Sorry about that.