env question?

Code:

#include<stdio.h>

int main(int argc, char *argv[], char *env[])
{
	int i;
	char *set_ABC;

	for(i = 0; env[i] != NULL; ++i)
		printf("%s\n", env[i]);
	set_ABC ="Try me!";
	return 0;
	}

i used this program to list env's but my question was if set ABC="Try me!" was entered would it be among the others or at the end?
Whats this...
c:\program files\microsoft visual studio\myprojects\ch14_ex1\ex1.cpp(10) : error C2440: '=' : cannot convert from 'char [8]' to 'char'

your first bit of code prints all the enviornment vars. nothing i can think of wrong with it.

your other piece of code however is totally unrelated to environment vars. try allocating space for set_ABC first rather than using it unitizalized and then using strcpy () to put "try me!" in it. but what does that have to do with enviornment vars?

Code:

set_ABC ="Try me!";

You can only do this during initialization. Otherwise you would need to use strcpy()

I donno, the book i bought to study this asks only whether this is listed among env aplhabetically or at the end? So far my success has been a failure but i will try what you two said.
Thanks!
cj.

>You can only do this during initialization.
No, this is a valid operation. The pointer is being made to point at a string literal.

The problem is the last brace, it shouldn't be there and the compiler is complaining.

-Prelude

ways to define a string in C:

Code:

char foobar[] = "Hello";

char foobar[6] = "Hello"; // note 6 not 5, last is for null terminator

char *foobar = "Hello"; // set at initialization - is ok

char *foobar;
foobar = (char *) malloc (6); // allocate space
strcpy (foobar, "Hello"); // after initialization you must use string functions to change strings
free (foobar); // anything malloc()ed must be free()d after you're done with it

the first and second examples above can also have strcpy() used on them, but not outside of the space you have to work with! otherwise you'll be reaching into memory that's not yours.
the third example above should not be modified after initalization (thanks hammer).

Code:

char *foobar;
foobar = (char *) malloc (strlen ("Hello") + 1); // strlen returns the size of the inputted string
strcpy (foobar, "Hello");
free (foobar); // always free after your done using it, never free before

god i hope that's all right (it looks right to me) otherwise i'm gonna feel sofa king dumb

Code:

1- char foobar[] = "Hello";
2- char foobar[6] = "Hello"; // note 6 not 5, last is for null terminator
3- char *foobar = "Hello"; // set at initialization - is ok

the first three examples can also have strcpy() used on them after initilization.

One thing... you cannot do this on option 3 (above)
>char *foobar = "Hello";
>strcpy(foobar, "blurb");
This is because the pointer is pointing to a string literal which cannot be safely modified.