stupid question about converting floats to long ints...

When I compile the program below, it throws up warnings about this statement:

Code:

  loopspersec = lps / spd;

because I'm trying to assign a Long Int from a Float.

My question:
Is there any function to convert a float to an integer?

Code:

#include <stdio.h>
#include <time.h>
#include <stdlib.h>
#include <limits.h>
#include <math.h>

#define TOTAL_LOOPS 500000000

int main (void)
{
  clock_t s, e;
  float spd, dur;
  long loopspersec;
  long lps;
  
  if( TOTAL_LOOPS > LONG_MAX)
  {
   printf("Hmmm, this shouldn't happen.");
   return -1;
  }
  
  s = clock();  
  for (lps = 0; lps < TOTAL_LOOPS; lps++ );
  e = clock();
 
  dur = e - s;
  spd = dur / CLOCKS_PER_SEC;
  loopspersec = lps / spd;
  
  printf ( "%ld Loops in %f seconds.\n", lps, spd );
  printf ( "%ld Loops per second.\n", loopspersec);
  system("PAUSE");
  return 0;
}

The warning is about a loss of precision when you convert a float to a long. To remove this warning, you can cast the result of the division to long.

>loopspersec = lps / spd;
loopspersec = (long)(lps / spd);

Though a better method would be to use float for loopspersec. That way you can simply ignore everything past the decimal and you have the added advantage of being able to hold larger values.

-Prelude

Just what I needed, thanks