need a second pair of eyes to debug

This is just a piece of the code but I believe the problem the is in the function where '\n' is read along with the input, therefore everthing is FLASE. (please tell me if Im wrong.) So I tried to allow \n but

Code:

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if (( !isdigit ( *max++)) && max != '\n')

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Didnt work either.:confused: Any suggestions are welcome. Thnx

Code:

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static int validate_whole ( char *max )
{
        while ( *max != '\0' )
                if ( !isdigit ( *max++)
                        return BOOL_FALSE;
        return BOOL_TRUE;
}


int main (void)
{
        int maxnum;
    char max[BUFSIZ];

        printf("How many numbers would you like to sort [2-20]: ");
        fgets( max, BUFSIZ, stdin);
       
        while( validate_whole (max) == BOOL_FALSE )
        {
                printf("Invalid entry, The number must be between 2 and 20\n");
                printf("\nHow many numbers would you like to sort [2-20]: ");
                fgets( max, BUFSIZ, stdin);               
        }

#if 1
                //maxnum = atoi( max );
                sscanf(max, "%d", &maxnum );
#endif

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Add the following directly after the scanf() call to remove the trailing newline character:

Code:

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#include <string.h>
....
fgets(......);
max[strcspn(max, "\n")] = '\0';  /* Add this line */

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within that same function

Code:

---

static int validate_whole ( char *max )
{
        while ( *max != '\0' )
                if ( !isdigit ( *max++))
                        return BOOL_FALSE;
        return BOOL_TRUE;
}

---

If I wanted to narrow the range of numbers they can enter. For example between 5 and 30, everything else returns false.

Obviously this would be much easier if it was an int but because we are dealing with a char and possibly 2 elements (ie.. 10 11 12 etc), Im not sure which is the best way to approach it. With my limited knowledge I could do it the long way but Im hoping you gurus might know a shortcut.

There are various ways to do what you ask. One is to convert the string to an int using atoi(), then you can use a straight forward numeric test.

somethign like this?

Code:

---

static int validate_whole ( char *max )
{
        int maxnum;

        while ( *max != '\0' )
                if ( !isdigit ( *max++))
                        return BOOL_FALSE;

        maxnum = atoi( max );

        if( maxnum < '2' || maxnum > '20' )
                return BOOL_FALSE;

        return BOOL_TRUE;
}

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>if( maxnum < '2' || maxnum > '20' )
nearly, try
>if( maxnum < 2 || maxnum > 20 )

sorry to keep asking but this has me baffeled.....

I changed a few things to simplify it and to debug.

When I put this:

Code:

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maxnum = atoi( max );
if( maxnum > 20 )
    return BOOL_TRUE;
else
    return BOOL_FALSE;

---

it denies ALL integers

when I use::

Code:

---

maxnum = atoi( max );
if( maxnum < 20 )  // **LESS THAN 20**
    return BOOL_TRUE;
else
    return BOOL_FALSE;

---

it accepts ALL integers...

Any ideas?

Your problem is that you increment the max pointer variable within the loop in the validate function. Once you have incremented it to the end of the string, it no longer points to the start of it. Therefore, you cannot use it as a parameter to atoi() because it doesn't point to the right place.

Try something like this:

Code:

---

static int validate_whole ( char *max )
{       
        char *savemax = max;
        int maxnum;       
        while ( *max != '\0' )
                if ( !isdigit ( *max++))
                        return BOOL_FALSE;       
       
        maxnum = atoi( savemax );
        printf ("maxnum %d\n", maxnum);
        if( maxnum < 2 || maxnum > 20 )               
                return BOOL_FALSE;       
        return BOOL_TRUE;
}

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