Thread: What is the effect of this?

Here is the following recursive program

[code]
#include<stdio.h>

void Mystery(int A[], int size)
{
if (size > 0) {A[0] = 0; Mystery (A+1, size -1);}
}

int main(void)
{
int A
Mystery ();
return 0;
}
[/code

a. Its sets 1st element of array A to 0.
b. sets last ...
c. sets all...
d. generates an infinite recursion loop
Now before anyone comes up with any smart comments. I already wrote a program to see and it should be obvious that it did not work because i chose ans. D. Now you can either help or not, the choice is up to you?
Thanks to anyone who does.

Code:

int main(void)
{
int A

1) You forgot a ;

2) A is not an array.

Quzah.

1) You forgot a ;

2) A is not an array.

Quzah.



What do you mean Quzah? Educate me? I still do not understand.

It seems like your intentions were more along the lines of:

Code:

#include<stdio.h> 
#define SIZE 10

void Mystery(int A[], int size) 
{ 
   if (size > 0) {A[0] = 0; Mystery (A+1, size -1);} 
} 

int main(void) 
{ 
   int i;
   int A[SIZE];
   for(i = 0; i < SIZE; i++)
      A[i] = -1;
   Mystery (A, 4);
   for(i = 0; i < SIZE; i++)
      printf("A[%d] = %d\n", i, A[i]);
   return 0; 
}

This function recursively sets your elements to 0. In this case, I passed in the address of A[0] with size of 4. Therefore the first four elements A[0]...A[3] will be set to 0.

Hope that helps

it did alot.
thanks Cshot!